Answer:
Mass = 132 g
Explanation:
Given data:
Mass of CO₂ formed = ?
Mass of C burnt = 36 g
Solution:
Chemical equation:
C + O₂ → CO₂
Number of moles of carbon:
Number of moles = mass/molar mass
Number of moles = 36 g/ 12 g/mol
Number of moles = 3 mol
now we will compare the moles of carbon and carbon dioxide.
C : CO₂
1 : 1
3 : 3
Mass of CO₂:
Mass = number of moles × molar mass
Mass = 3 mol × 44 g/mol
Mass = 132 g
Answer:
C₂H₃Cl₃O₂
Explanation:
Given parameters:
Percentage composition:
14.52% C
1.83% H
64.30% Cl
19.35% O
Molar mass = 165.4 g/mo
Unknown:
Empirical formula = ?
Solution:
The empirical formula of a compound is the simplest formula of a compound. To solve this problem, let us follow the process below:
C H Cl O
%composition 14.52 1.83 64.3 19.35
Molar mass 12 1 17 16
number of
moles 14.52/12 1.83/1 64.3/3.5 19.35/16
1.21 1.83 1.81 1.21
Divide by
the smallest 1.21/1.21 1.83/1.21 1.81/1.21 1.21/1.21
1 1.51 1.51 1
multiply
by 2 2 3 3 2
Empirical formula C₂H₃Cl₃O₂
