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2 years ago

I need help, please answer

Chemistry

2 answers:

Ivanshal [37]2 years ago

8 0

Answer:

Mrs girl I'm sorry I don't know

I just need the points

djyliett [7]2 years ago

5 0

Answer:

it explodes

Explanation:

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BRAINLIESTT ASAP! PLEASE HELP ME :) Compare stored mechanical energy and mechanical energy.

UNO [17]

Stored mechanical energy is energy stored and awaiting to be used and mechanical energy is the energy that was stored being used.

6 0

3 years ago

Several properties of water are shown. Classify each property as a physical property or a chemical property.

max2010maxim [7]

can be split into hydrogen and oxygen chemical property

is liquid at room temperature physical property

has a density of 1.0 g/cm³ physical property

reacts with certain metals chemical property

Explanation:

The physical properties of matter are the properties that occur when no change is occurring to a matter. They are usually observed with our senses or some simple laboratory experiments.

Some of the physical properties are boiling point, density, state of matter, e.t.c

The chemical properties are the properties that occurs when a matter undergoes some chemical changes.

For example rusting, decomposition, reactivity e.t.c

Learn more:

Chemical properties brainly.com/question/2376134

#learnwithBrainly

8 0

3 years ago

The percent by mass of bicarbonate (HCO3−) in a certain Alka-Seltzer product is 32.5 percent. Calculate the volume of CO2 genera

nevsk [136]

Answer:

The volume of carbon dioxide gas generated 468 mL.

Explanation:

The percent by mass of bicarbonate in a certain Alka-Seltzer = 32.5%

Mass of tablet = 3.45 g

Mass of bicarbonate = $3.45 g\times \frac{32.5}{100}=1.121 mol$

Moles of bicarbonate ion = $\frac{1.121 g/mol}{61 g/mol}=0.01840 mol$

$HCO_3^{-}(aq)+HCl(aq)\rightarrow H_2O(l)+CO_2(g)+Cl^-(aq)$

According to reaction, 1 mole of bicarbonate ion gives with 1 mole of carbon dioxide gas , then 0.01840 mole of bicarbonate ion will give:

$\frac{1}{1}\times 0.01840 mol=0.01840 mol$ of carbon dioxide gas

Moles of carbon dioxide gas n = 0.01840 mol

Pressure of the carbon dioxide gas = P = 1.00 atm

Temperature of the carbon dioxide gas = T = 37°C = 37+273 K=310 K

Volume of the carbon dioxide gas = V

$PV=nRT$ (ideal gas equation)

$V=\frac{nRT}{P}=\frac{0.01840 mol\times 0.0821 atm L/mol K\times 310 K}{1.00 atm}=0.468 L$

1 L = 1000 mL

0.468 L =0.468 × 1000 mL = 468 mL

The volume of carbon dioxide gas generated 468 mL.

5 0

3 years ago

Molybdenum (Mo) has a body centered cubic unit cell. The density of Mo is 10.28 g/cm3. Determine (a) the edge length of the unit

ser-zykov [4K]

Answer:

For a: The edge length of the unit cell is 314 pm

For b: The radius of the molybdenum atom is 135.9 pm

Explanation:

For a:

To calculate the edge length for given density of metal, we use the equation:

$\rho=\frac{Z\times M}{N_{A}\times a^{3}}$

where,

$\rho$ = density = $10.28g/cm^3$

Z = number of atom in unit cell = 2 (BCC)

M = atomic mass of metal (molybdenum) = 95.94 g/mol

$N_{A}$ = Avogadro's number = $6.022\times 10^{23}$

a = edge length of unit cell =?

Putting values in above equation, we get:

$10.28=\frac{2\times 95.94}{6.022\times 10^{23}\times (a)^3}\\\\a^3=\frac{2\times 95.94}{6.022\times 10^{23}\times 10.28}=3.099\times 10^{-23}\\\\a=\sqrt[3]{3.099\times 10^{-23}}=3.14\times 10^{-8}cm=314pm$