Y=5-2x
x^2 + (5-2x)^2 = 25
x^2 + 25-20x+4x^2 = 25
x^2 +4x^2-20x+25=25
5x^2 -20x=0
x=0 and y=5
Answer:
n=35
Step-by-step explanation:
-3(n-16)= -57
-3n+48= -57
-48 -48
-3n= -105
/-3 /-3
n= 35
10 n = C
Finding the total would simply be multiplying the cost of the tickets by number of students.
Answer: 35 inches.
Step-by-step explanation:
We know that:
hypotenuse = 5*y in
cathetus 1 = (x + 8) in
cathetus 2 = (x + 3) in
The perimeter of the triangle is 76 inches, then:
5*y + (x + 8) + (x + 3) = 76
5*y + 2*x + 13 = 76
We also know that the length of the hypotenuse minus the length of the shorter leg is 17 in.
The shorter leg is x + 3, then:
5*y - (x + 3) = 17
Then we have the equations:
5*y + 2*x + 11 = 76
5*y - (x + 3) = 17
With only these two we can solve the system, first we need to isolate one of the variables in one of the equations, i will isolate x in the second equation.
x = 5*y - 3 - 17 = 5*y - 20
x = 5*y - 20
Now we can replace this in the other equation, we get:
5*y + 2*x + 11 = 76
5*y + 2*(5*y - 20) + 11 = 76
15*y - 40 + 13 = 76
15*y - 29 = 76
15*y = 76 + 29 = 105
and remember that the hypotenuse is equal to 5*y, then we want to get:
3*(5*y) = 105
5*y = 105/3 = 35
5*y = 35
Then te length of the hypotenuse is 35 inches.
Answer: I say B
Step-by-step explanation:
