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olganol [36]
3 years ago
8

The game is played by Drawing five white balls out of a drum of 69 white balls (numbered 1-69) and one red power bowl out of a d

rum 26 red balls (numbered 1-29) The jackpot is one by matching all five white balls in any order in the red Powerball.
Mathematics
1 answer:
blsea [12.9K]3 years ago
5 0

Answer:

The expected value for purchasing one ticket for the jackpot = $77.26

Step-by-step explanation:

We first compute the probability mass function for the problem.

Probability of winning the jackpot

One has to get all 5 white ball and the one red ball correctly. There are 69 white balls and 26 red balls.

5 white balls can be selected from 69 with order not important, and 1 red ball selected from 26 red balls in

⁶⁹C₅ × ²⁶C₁ ways = 292,201,338 ways

And there are (5! × 1) different combinations of those winning numbers = 120 combinations (since order isn't important for the 5 numbers of the white balls)

Required Probability of winning

= (120 ÷ 292,201,338) = 0.0000004107

= (4.107 × 10⁻⁷)

To win, one would buy a $2 ticket, and win $193 million.

Amount of winnings = 193,000,000 - 2 = $192,999,998

Probability of losing = 1 - (Probability of winning) = 1 - (4.107 × 10⁻⁷) = 1

To lose, one would buy a $2 ticket and win nothing.

Amount of winnings = 0 - 2 = -$2

So, the probability mass function

X | 192,999,998 | -2

p | (4.107 × 10⁻⁷) | 1

Expected value = E(X) = Σ xᵢpᵢ

E(X) = [(192,999,998) × (4.107 × 10⁻⁷)] + (-2)(1)

E(X) = 79.26 - 2 = $77.26

Hope this Helps!!!

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Step-by-step explanation:

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8 0
2 years ago
3x − 2y = −2
Lina20 [59]

Answer: C. -3y+14

Step-by-step explanation:

3x-2y=-2\\x+3y=14

Move 3y to ther right side.

3x-2y=-2\\x=-3y+14

So the answer is C. Because x = -3y+14.

7 0
3 years ago
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Can i get help on this one ? im almost running our of points i would give 50 but i need more ;-; anyway
JulsSmile [24]

Answer:

Step-by-step explanation:

Let x = third side

Using the Triangle Inequality theorem which states that the sum of two sides of a triangle must be longer than the third side and the difference of the two sides is the lower limit of the third side, the answer to your question is that the third side must be between 3 and 13, or written using inequalities, 3 < third side (or x) < 13 is the range.

4 0
3 years ago
a traveler has 7 pieces of luggage . how many ways can the traveler select 3 pieces of luggage for a trip
7nadin3 [17]
Well, you could assign a letter to each piece of luggage like so...

A, B, C, D, E, F, G

What you could then do is set it against a table (a configuration table to be precise) with the same letters, and repeat the process again. If the order of these pieces of luggage also has to be taken into account, you'll end up with more configurations.

My answer and workings are below...

35 arrangements without order taken into consideration, because there are 35 ways in which to select 3 objects from the 7 objects.

210 arrangements (35 x 6) when order is taken into consideration.

*There are 6 ways to configure 3 letters.

Alternative way to solve the problem...

Produce Pascal's triangle. If you want to know how many ways in which you can choose 3 objects from 7, select (7 3) in Pascal's triangle which is equal to 35. Now, there are 6 ways in which to configure 3 objects if you are concerned about order.

7 0
3 years ago
A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40
malfutka [58]
PART A

The given equation is

h(t) = - 16 {t}^{2} + 40t + 4

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4

We add and subtract

- 16(- \frac{5}{4} )^{2}

to get,

h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4

We again factor -16 out of the first two terms to get,

h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4

This implies that,

h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4

The quadratic trinomial above is a perfect square.

h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4

This finally simplifies to,

h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29

The vertex of this function is

V( \frac{5}{4} ,29)

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

29

PART B

When the ball hits the ground,

h(t) = 0

This implies that,

- 16 ( t- \frac{5}{4}) ^{2} +29 = 0

We add -29 to both sides to get,

- 16 ( t- \frac{5}{4}) ^{2} = - 29

This implies that,

( t- \frac{5}{4}) ^{2} = \frac{29}{16}

t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }

t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}

t = \frac{ 5 + \sqrt{29} }{4} = 2.60

or

t = \frac{ 5 - \sqrt{29} }{4} = - 0.10

Since time cannot be negative, we discard the negative value and pick,

t = 2.60s
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