Answer:
36365.4 Joules
Explanation:
The quantity of Heat Energy (Q) released on cooling a heated substance depends on its Mass (M), specific heat capacity (C), and change in temperature (Φ)
Thus, Q = MCΦ
Since, M = 45.4 g
C = 3.56 J/g°C,
Φ = 250°C - 25°C = 225°C
Q = 45.4g x 3.56J/g°C x 225°C
Q= 36365.4 Joules
Thus, 36365.4 Joules of heat energy is released when the lithium is cooled.
Answer: The statement is not correct because the decrease in entropy of the hot solid CANNOT BE equal to the increase in entropy of the cold one
Explanation:
Let us start by stating the second law of thermodynamics and it the second law of thermodynamics states that there is an entity called entropy and entropy will always increase all the time. Also, the second law of thermodynamics states that the change in entropy can never be negative. The second law of thermodynamics can be said to be equal to Change in the transfer of heat, all divided by temperature.
So, the first law of thermodynamics deals with the conservation of energy. But there is nothing like conservation of entropy.
Therefore, the decrease in entropy of the hot solid CANNOT BE equal to the increase in entropy of the cold one because entropy is not a conserved property.
Answer:
the energy value of the olive oil kJ/g = 36.880 KJ/g
Explanation:
we can calculate energy gained by the water which generated by the reaction from this formula :
Q = mc∆t
where:
m is the mass of water= 370 g
c specific heat of water = 4.184 J/g·°C
∆t is the change or difference in temperature in °C = 38.9 - 22.7 = 16.2 °C
by substitution:
Q = 370g * 4.184 J/g.°C* 16.2°C
= 25078.896 Joule
the energy value of the olive oil = Q / mass of olive oil
= 25078.896 Joule/ 0.68 g
=36880 J/g
= 36880 / 1000 = 36.880 KJ/g
<u>Answer:</u> The net ionic equation is written below.
<u>Explanation:</u>
Net ionic equation of any reaction does not include any spectator ions.
Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.
The chemical equation for the reaction of calcium iodide and chromium (III) sulfate is given as:
Ionic form of the above equation follows:
As, chromium and iodide ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.
The net ionic equation for the above reaction follows:
Hence, the net ionic equation is written above.
Answer:
100.8 °C
Explanation:
The Clausius-clapeyron equation is:
-Δ
Where 'ΔHvap' is the enthalpy of vaporization; 'R' is the molar gas constant (8.314 j/mol); 'T1' is the temperature at the pressure 'P1' and 'T2' is the temperature at the pressure 'P2'
Isolating for T2 gives:
(sorry for 'deltaHvap' I can not input symbols into equations)
thus T2=100.8 °C
