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sashaice [31]
3 years ago
13

Write the net ionic equation for any precipitation reaction that may be predicted when aqueous solutions of calcium iodide and c

hromium(III) sulfate are combined. (Use the solubility rules provided in the OWL Preparation Page to determine the solubility of compounds.)
Chemistry
1 answer:
Hitman42 [59]3 years ago
8 0

<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of calcium iodide and chromium (III) sulfate is given as:

3CaI_2(aq.)+Cr_2(SO_4)_3(aq.)\rightarrow 3CaSO_4(s)+2CrI_3(aq.)

Ionic form of the above equation follows:

3Ca^{2+}(aq.)+6I^{-}(aq.)+2Cr^{3+}(aq.)+3SO_4^{2-}(aq.)\rightarrow 3CaSO_4(s)+2Cr^{3+}(aq.)+6I^-(aq.)

As, chromium and iodide ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

3Ca^{2+}(aq.)+3SO_4^{2-}(aq.)\rightarrow 3CaSO_4(s)

Hence, the net ionic equation is written above.

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Answer:contains as much solvent as it can hold

Explanation:

A saturated solution is a solution that contains just as much solute as it can normally hold at a particular temperature. A saturated solution has just the right amount of solute dissolved in it to give a clear solution. More solute will not dissolve after saturation.

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An experiment is carried out to determine how different pH values of soil will affect the growth of tomato
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Answer:

How high the plants grow in the different soils.  

Explanation:

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5 0
4 years ago
How can you apply a covalent bond?
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2. If 5.4 g Al are reacted with excess HCI, how many moles of H2 will be produced?
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Answer:

0.3 moles of H2 will be produced.

Explanation:

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Using the formula:

moles = mass / Mr

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moles of Al = 0.2 moles

Here we see that "2" molar mass before Al; so in this reaction, "1" molar mass will have [(0.2)/2] = 0.1 moles. He see "3" molar mass before H2, therefore moles of H2 is (3 * 0.1) = 0.3 moles.

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