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leva [86]
2 years ago
12

All the following process produces hematite except

Chemistry
1 answer:
katovenus [111]2 years ago
3 0

Answer:

D)driying of limonite these is the answer

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Twenty irregular pieces of an unknown metal have a collective mass of 28.225 g. When carefully placed in a graduated cylinder th
Lelechka [254]

Explanation:

Use the density formula to determine the volume of the piece of metal.

density

=

mass

volume

Rearrange the equation to isolate volume.

volume

=

mass

density

volume

=

147

g

7.00

g

mL

=

21.0 mL

The final volume in the cylinder after adding the piece of metal is

20.0 mL

+

21.0 mL

=

41.0 mL

8 0
3 years ago
Simple distillation is best used to separate two liquids that have boiling points that differ by
emmasim [6.3K]
The boiling points need to differ by 50 degrees to enable their complete separation ie of two different liquids. The separation occurs by first evaporation of one of the liquids and then its condensation and collection. It is a physical process not a chemical one.
6 0
3 years ago
What is the molar mass of CO2
mina [271]
Molar mass of CO2 = 44.01 g/mol
5 0
3 years ago
Which of Graphs 1 correctly represents the relationship between the pressure and volume of a gas?
Alborosie

Answer:

D

Explanation:

pressure is inversely proportional to gas volume

4 0
2 years ago
60 grams of ice will require _____ calories to raise the temperature 1°C.
guajiro [1.7K]

Answer:

60 grams of ice will require 30.26 calories to raise the temperature 1°C.

Explanation:

The amount of heat (Q) to raise the temperature of 60.0 g of ice by 1°C can be calculated from:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of heat released or absorbed by the system.

m is the mass of the ice (m = 60.0 g).

c is the specific heat capacity of ice (c = 2.108 J/g.°C).

ΔT is the temperature difference (ΔT = 1.0 °C).

∴ Q = m.c.ΔT = (60.0 g)(2.108 J/g.°C)(1.0 °C) = 126.48 J.

<em>It is known that 1.0 cal = 4.18 J.</em>

<em>∴ Q = (126.48 J)(1.0 cal / 4.18 J) = 30.26 cal.</em>

7 0
3 years ago
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