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Agata [3.3K]
3 years ago
6

HELP ME ASAP PLEASE HURRY!

Mathematics
2 answers:
Romashka [77]3 years ago
8 0

Answer:

It should be 11 units

Mice21 [21]3 years ago
7 0

Answer:

9.2

Step-by-step explanation:

Use the Pythagorean Theorem a^2+b^2=c^2

2^2+9^2=c^2\\4+81=c^2\\85=c^2\\c=\sqrt{85} \\c=9.2

You might be interested in
3m + 5 = 8 modeled by algebra tiles
Lesechka [4]
3m+5=8
subtract 5 from both sides
3m=3
divide both sides by 3
m=1

I hope I helped! :)
4 0
3 years ago
Read 2 more answers
The box plots show the weights, in pounds, of the dogs in two different animal shelters.
zimovet [89]

*see attachment below for the box plots that is being referred to

Answer:

*The median weight for shelter A is greater than that for shelter B

*The data for shelter B are a symmetric data set

Step-by-step explanation:

Let's take each stated option and examine the box plot to see which is TRUE or NOT.

OPTION 1: "The median weight for shelter A is greater than that for shelter B."

The median for shelter A = 21,

Median for shelter B = 18

Median weight for shelter A (21) is greater than that for shelter B.

This statement in this option is TRUE.

OPTION 2: "The median weight for shelter B is greater than that for shelter A."

Median for B (18) < median of A (21)

This statement in option is NOT TRUE.

OPTION 3: "The data for shelter A are a symmetric data set."

This is NOT TRUE because the length of both whiskers are unequal and also, the box is not divided equally. One side is longer than the other.

OPTION 4: "The data for shelter B are a symmetric data set."

This is TRUE because the length of both whiskers are relatively equal, and also, the rectangular box is divided equally.

OPTION 5: "The interquartile range for shelter A is 8"

This is NOT TRUE.

IQR = Q3-Q1

IQR for shelter A is approximately  = 28-17 = 11

5 0
3 years ago
If n+h/5=f+9/9, then n/5=
Ann [662]
------------------------------------------------------------------
Question
------------------------------------------------------------------
\boxed { \frac{n+h}{5}  =  \frac{f+9}{9}}

------------------------------------------------------------------
Split the fraction on the left
------------------------------------------------------------------
\boxed { \frac{n}{5} + \frac{h}{5}  = \frac{f + 9}{9}}

------------------------------------------------------------------
Take away h/5 from both sides
------------------------------------------------------------------
\boxed { \frac{n}{5}  = \frac{f+9}{9} - \frac{h}{5}}

------------------------------------------------------------------
Change the denominator to be the same
------------------------------------------------------------------
\boxed { \frac{n}{5} = \frac{5f+45}{45} - \frac{9h}{45}}

------------------------------------------------------------------
Put it into single fraction
------------------------------------------------------------------
\boxed { \frac{n}{5} = \frac{5f+45-9h}{45} }

-------------------------------------------------------------------
Rearrange (This step may not be necessary)
------------------------------------------------------------------
\boxed {\frac{n}{5} = \frac{5f-9h+ 45}{45} }


\bf \Longrightarrow \ Answer \ : \boxed {\boxed {\frac{n}{5} = \frac{5f-9h+ 45}{45} }}

6 0
3 years ago
Nancy sells handcrafted bracelets at a flea market for $6. If her monthly fixed costs are $625 and each bracelet cost her $1.75
Mandarinka [93]
148, 6-1.75=5.25, then.... 625/5.25& round up.... its 148.
7 0
3 years ago
Which statement illustrates the distributive property?
puteri [66]

Answer:

3(4+5)= 3(4)+3(5)

Step-by-step explanation:

5 0
3 years ago
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