which equation is in slope intercept form and represents a line with slope 3 through the point (9,-4)?

Mathematics

1 answer:

faust18 [17]3 years ago

4 0

Answer:

y = 3x - 23

Step-by-step explanation:

y + 4 = 3(x - 9)

y + 4 = 3x - 27

y = 3x - 23

You might be interested in

Its really urgent. I need help with the first question.

RUDIKE [14]

This kind of exercise can be real drudgery. But it's almost all simple arithmetic, so better you than me. I'll do one of these for you, which will show you how to do the other one.

a). sin · cot / sec

You're supposed to know that [ cotangent = cosine/sine ]
and [ secant = 1/cosine ].

Then the problem becomes

sin · (cos/sin) / (1/cos) = cos²

Aw shucks, I might as well also set up 'b)' for you:

b). cos · csc / tan

You're supposed to know that [ cosecant = 1/sine ]
and [ tangent = sine/cosine ].

Then the problem becomes

cos · (1/sin) / (sin/cos) = (cos/sin)²

Now simply plug in the given values of cos A and sin A .

And may I compliment you on your nail care !

7 0

3 years ago

Graph the following system of equations. Click on the graph until the correct graph appears.

nikdorinn [45]

Answer:

See explanation

Step-by-step explanation:

1. Draw the dotted line y=-x. This line must be dotted, because the inequality y<-x is with sign < (without notion "or equal to"). Then shade the region that contains all values of y that are less than -x (bottom part that is shaded in red on the attached diagram).

2. Draw the solid line y=x-2. This line must be solid, because the inequality y≤x-2 is with sign ≤ (with notion "or equal to"). Then shade the region that contains all values of y that are less or equal to x-2 (bottom part that is shaded in blue on the attached diagram).

3. Their common part (region that is shaded in both red and blue colors) represents both inequalities.