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goldenfox [79]
3 years ago
13

Please help with 7 ,8 ,9, 10 , 11 pleasee

Chemistry
1 answer:
fenix001 [56]3 years ago
6 0
8 is low tide 9 is c
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Animals breathe oxygen and release carbon dioxide during cellular respiration according to the equation below. How much oxygen i
kifflom [539]

Answer:

14.544 g of oxygen is needed to produce 120 grams of carbon dioxide.

Explanation:

Animals take in oxygen and breathe out carbon dioxide during cellular respiration. The reaction for the metabolism of the food in the animal body is:

C_6H_{12}O_6 + O_2 \rightarrow 6CO_2 + 6H_2O + Energy

As can be seen from the reaction stoichiometry that:

<u>6 moles of carbon dioxide gas can be produced from 1 mole of oxygen gas in the process of metabolism of glucose.</u>

Also,

Given :

Mass of carbon dioxide gas = 120 g

Molar mass of carbon dioxide gas = 44 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus, moles of carbon dioxide are:

moles_{CO_2} = \frac{120 g}{44 g/mol}

moles_{CO_2} = 2.7273 mol

As mentioned:

<u>6 moles of carbon dioxide</u> gas can be produced from <u>1 mole of oxygen gas</u> in the process of metabolism of glucose.

<u>1 mole of carbon dioxide</u> gas can be produced from <u>1/6 mole of oxygen gas</u> in the process of metabolism of glucose.

<u>2.7273 mole of carbon dioxide</u> gas can be produced from <u>\frac{1}{6} \times 2.7273 moles of oxygen gas</u> in the process of metabolism of glucose.

Thus, moles of oxygen gas needed = 0.4545 moles

Molar mass of oxygen gas = 32 g/mol

The mass of oxygen gas can be find out by using mole formula as:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Mass\ of\ oxygen\ gas = Moles \times Molar mass}

Mass\ of\ oxygen\ gas = 0.4545 \times 32}

Mass\ of\ oxygen\ gas = 14.544 g

<u>14.544 g of oxygen is needed to produce 120 grams of carbon dioxide.</u>

3 0
3 years ago
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Shalnov [3]
The answer is 196.96655.
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Describe three skills people use to conduct scientific investigations
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Observations, surveys, and models.
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3 years ago
A measurement 172.54 m rounded to three significant figures is
xxTIMURxx [149]
173.00m
Step by step explanation
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Pls mark brainliest
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3 years ago
How many formula units are contained in 2.35mol of Iron (III) Oxide
konstantin123 [22]
Remember, 1 mole= 6.022x10^23 atoms, molecules, or formula units.

Answer is 1.42x10^24

7 0
3 years ago
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