Question

the ph of a solution of HCl in water is found to be 2.50. what volume of water would you add to 1.00L of this solution to raise the pH to 3.10​

Answer 1

Answer:

To raise the pH of the solution to 3.10 we have to add 2.34 L of water.

Explanation:

Given that the pH of the solution of HCl in water is 2.5.  Here the solution’s pH is changing from 2.5 to 3.10 which means the acidic nature of the solution is decreasing here on dilution. $[H^+]$ ions contribute to a solution’s acidic nature and $[OH^-]$contribute to a solution’s basic nature.

The equation connecting the concentration of $[H^+]$ and pH of a solution is pH= $-log[H^+]$

$[H^+]= 10^(^-^p^H^)$$[H^+]= 10^(^-^2^.^5^)=0.00316$

When the pH is $3.1 [H^+ ]= 10^(^-^3^.^1^)=0.000794$

On dilution the concentration of a solution decreases and volume increases.

$M_1 V_1 = M_2 V_2$

$0.00316 \times 1 = 0.000794 \times V_2$

$V_2 = \frac{(0.00316 \times 1)}{0.000794} =3.24$

Volume of water to be added $=3.24-1$

$=2.24L$