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2 years ago

PLEASE HURRY IM TIMED Which of the following are examples of physical changes? (Select all that apply.)

Chemistry

1 answer:

stich3 [128]2 years ago

3 0

Answer:

Explanation:

tearing a piece of paper

crushing a soda can

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Which of the following statements is a qualitative observation? A.The branch is three meters long. B.The substance tastes bitter

notka56 [123]

There are two kinds of analysis: qualitative and quantitative

In quantitative we analyse the amount of something that is how much of something is present / the quantity. Ex: the length of branch of tree, number of students in class, volume of a liquid in a beaker.

In qualitative analysis we determine the kind of substance / quality of substance / nature of substance.

like: colour of a substance, odor of a substance or taste (bitter / sour / sweet etc) of a substance

So answer is : B.The substance tastes bitter

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2 years ago

Sodium hydrogen carbonate and citric acid<br><br> Word equation

timofeeve [1]

Answer:

the right answer is:

Explanation:

How to Balance: NaHCO3 + HC2H3O2 = NaC2H3O2 + CO2 + H2O|

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2 years ago

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Calculate the PH of a solution 0.030 MH2SO4

Zinaida [17]

Answer:

pH= 2- log3

Explanation:

H2SO4 + H2O -> HSO4^(-) + H30^(+)

0.03M ___ ___

___ 0.03M 0.03M

H30^(+) : C = 0.03M

pH= - log( [H3O^(+)] ) => pH= - log {3× 10^(-2)} => pH = 2 - log3

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2 years ago

Which of the following is not equal to 0.536 kilometers? 53.6 hectometers (hm) 536 meters (m) 536,000 millimeters (mm) 53,600 ce

garri49 [273]

I believe it would be 53.6 hectometers, but I'm not 100% sure

8 0

2 years ago

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The equilibrium constant for the reaction 2NO(g)+Br2(g)⥫⥬==2NOBr(g) is Kc=1.3×10−2 at 1000 K. At this temperature does the equil

o-na [289]

Answer :

The equilibrium favors NO and $Br_2$ .

(1) The value of equilibrium constant for this reaction is, 76.9

(2) The value of equilibrium constant for this reaction is, 8.77

Explanation:

The given chemical equation is:

$2NO(g)+Br_2(g)\rightarrow 2NOBr(g)$

The value of equilibrium constant for the above equation is $K_c=1.3\times 10^{-2}$ .

The value of $K_c$ that means equilibrium lies to the left side. Thus, the equilibrium favors NO and $Br_2$ .

We need to calculate the equilibrium constant for the given equation of above chemical equation, which is:

(1) $2NOBr(g)\rightarrow 2NO(g)+Br_2(g)$

The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.

The value of equilibrium constant for reverse reaction is:

$K_{c_1}=\frac{1}{K_c}$

$K_{c_1}=\frac{1}{1.3\times 10^{-2}}=76.9$

Thus, the value of equilibrium constant for this reaction is, 76.9

(2) $NOBr(g)\rightarrow NO(g)+\frac{1}{2}Br_2(g)$

The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.

If the equation is multiplied by a factor of '1/2', the equilibrium constant of the reverse reaction will be the 1/2 power of the equilibrium constant of initial reaction.

The value of equilibrium constant for reverse reaction is:

$K_{c_2}=(\frac{1}{K_c})^{1/2}$

$K_{c_2}=(\frac{1}{1.3\times 10^{-2}})^{1/2}=8.77$

Thus, the value of equilibrium constant for this reaction is, 8.77

7 0

2 years ago

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