Answer:
I think 512 feet in 16 seconds.
Answer:
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Step-by-step explanation:
Given that;
the frequencies of there alternatives are;
Frequency A = 60
Frequency B = 12
Frequency C = 48
Total = 60 + 12 + 48 = 120
Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;
Relative Frequency A = Frequency A / total = 60 / 120 = 0.5
Relative Frequency B = Frequency B / total = 12 / 120 = 0.1
Relative Frequency C = Frequency C / total = 48 / 120 = 0.4
therefore;
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
After plotting all the three points, we get the parabolic equation in the form is 2(x - 1)²-34.
<h3>What is parabola?</h3>
Any point on a parabola, which has the shape of a U, is situated at an equal distance from the focus, a fixed point, and the directrix, a fixed line.
General equation of the quadratic equation,
Y = ax² + bx +c
Given points,
(-2, 0),
(-1, -10),
(4, 0).
Putting the points in the general equation,
Putting (-2, 0), we get
0 = 4a - 2b + c
Putting (-1, -10), we get
-10 = a - b +c
Putting (4, 0), we get
0 = 16a + 4b +c
Solving all equations we get,
a = 2 , b = -4 , c = -16
After putting the values,
Y = 2x²- 4x- 16
2(x² - 2x - 8)
2(x²- 2x + 1 - 1 - 16)
=2(x - 1)²-34
Hence we get the required equation in the parabolic form.
To know more about parabola, visit :
brainly.com/question/21685473
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There is no attachment to this questions so we do not know which table represents the following. If you re-question, I would be gladly able to do so.
Answer:
The ratio of a circle's circumference to its diameter
In other words: all the way around a circle divided by all the way across it.
The symbol is π (pi)
No matter how large or small the circle, its circumference is always π times its diameter.
π = 3.14159265358979323846... (the digits go on forever without repeating)
A rough approximation is 22/7 (=3.1428571...), but that is not accurate.
Step-by-step explanation: