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natita [175]
3 years ago
15

A fathom is a unit of length, usually reserved for measuring the depth of water. A fathom is exactly 6.00 ft in length. Take the

distance from Earth to the Moon to be 246,000 miles, and use the given approximation to find the distance in fathoms. 1 mile = 5280 ft. Note, this one needs to be in fathoms so make sure you include "fathoms" in the units
Physics
1 answer:
iragen [17]3 years ago
7 0

Answer:

216480000 fathoms

Explanation:

1 fathom = 6 feet

1\ feet=\frac{1}{6}\ fathom

Distance from Earth to the Moon = 246000 miles

Converting to feet

1 mile = 5280 feet

246000 miles = 1298880000 feet

Convert to fathom

1\ feet=\frac{1}{6}\ fathom\\\Rightarrow 1298880000\ feet=\frac{1298880000}{6}=216480000\ fathom

So, the distance between Earth and Moon is 216480000 fathoms

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Relate the output of energy from a heat engine to the energy put into the heat engine considering the second law of thermodynami
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<u>Answer: </u>

<em>Considering the II law of thermodynamics</em>

<em>From the figure</em>

<em>Out put of energy: </em>

Heat supplied from the source/ reservoir  (Q₁) - Heat rejected to the surroundings from the system (Q) = Q₁ - Q₂. Also known as Net work done on the system.

<em>Input of energy: </em>

Amount of heat energy supplied to the system from the source (Q₁ ).

Efficiency (H.E) = η = Output÷ Input

                             η  = (Q₁ - Q₂) ÷ Q₁

                      OR η = Wnet ÷ Q₁ ;        since Wnet = (Q₁ - Q₂)


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3 years ago
A spring extends by 10cm when a mass of 100g is attached to it. What is the spring constant?​
pishuonlain [190]

Answer:

10N/m

Explanation:

Using F=kx

F=mg

k=mg/x

k=0.1*10/0.1 (kg*m/s^2)/m

10N/m

8 0
3 years ago
Can someone plz help me.
Scilla [17]

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6 0
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When an atom that has no charge looses two electrons it becomes a
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Answer: it becomes a positive ion

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8 0
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What is the speed of a beam of electrons when under the simultaneous influence of E = 1.64×104 V/m B = 4.60×10−3 T Both fields a
andrezito [222]

Answer: v = 3.57×10^6 m/s; R = 4.42×10^-3m; T = 7.78×10^-9 s

Explanation:

Magnetic force(B) = 4.60×10^-3 T

Electric force(E) = 1.64×10^4 V/m

Both forces having equal magnitude ;

Magnetic force = electric force

qvB = qE

vB = E

v = (1.64×10^4) ÷ (4.60×10^-3)

v = 3.57×10^6 m/s

2.) Assume no electric field

qvB = ma

Where a = v^2 ÷ r

R = radius

a = acceleration

v = velocity

qvB = m(v^2 ÷ R)

R = (m×v) ÷ (|q|×B)

q=1.6×10^-19C

m = 9.11×10^-31kg

R = (9.11×10^-31 * 3.57×10^6) ÷ (1.6×10^-19 * 4.6×10^-3)

R = 32.5227×10^-25 ÷ 7.36×10^-22

R = 4.42×10^-3m

3.) period(T)

T = (2*pi*R) ÷ v

T = (2* 4.42×10^-3 * 3.142) ÷ (3.57×10^6)

T = (27.775×10^-3) ÷(3.57×10^6)

T = 7.78×10^-9 s

6 0
4 years ago
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