Question

1. How many Joules are absorbed by a pot of water with a mass of 500. g in order to

Answer 1

20920 joules of heat is absorbed by a pot of water with a mass of 500g in order to raise the temperature from 20°C to 30°C

Explanation:

mass of water=500g

final temperature=30°C

Initial temperature=20°C

change in temperature=30-20=10

specific heat of water=1 J/kg°C

$energy required=mass of water \times temperature difference\times specific heat\\=500 \times10 \times \1\\=5000 calories\\=5kcal$

1 kcal=4184 joules

$5 kcal=5 \times 4184=20920 joules$