4 years ago

HELP PLEASE WILL MARK BRAINLIEST!!

Mathematics

1 answer:

lilavasa [31]4 years ago

4 0

Answer:

the picture is blurry sorry can't help cause I can't see the question

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As a project for math class, two students devised a game in which 3 black marbles and 2 red marbles are put into a bag.

9966 [12]

Answer:

The first option

Step-by-step explanation:

The correct answer is the first option, since E(black) = 0.24 and E(red) = 0.16, Seth should choose to play black marbles.

7 0

3 years ago

Please help!! Will give brainliest! Giving lots of points!

olga nikolaevna [1]

Answer:

d) $(9*3/4)+y$

Step-by-step explanation:

b) $9+y*(3/4)$

This expression is not equivalent, as the original expression, $y+9*\frac{3}{4}$ , has 9 multiplied to $\frac{3}{4}$ instead of y. You can interchange values like this when it comes to addition, but not multiplication.

c) $(y+9)(3/4)$

This expression is also not equivalent. After opening up the parentheses, it would again result in y being multiplied to $\frac{3}{4}$ .

$(y+9)(3/4)\\= y(3/4)+9(3/4)$

d) $(9*3/4)+y$

This expression is equivalent, as 9 and $\frac{3}{4}$ are still being multiplied together and y is added to the product. We can actually rearrange this to look like the original expression:

$(9*3/4)+y\\=y+(9*3/4)\\=y+(9*\frac{3}{4} )\\=y+9*\frac{3}{4}$