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Rudik [331]
4 years ago
15

Which relationship is continuous? A) The distance a runner ran during training B) The number of cookies Stan backed for the part

y C) The number of people attending the assembly D) The number of cows a farmer has owned over the years
Mathematics
1 answer:
tatyana61 [14]4 years ago
4 0
(A)The distance a runner ran during training......
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I have lots of math questions and I need help!
ad-work [718]
The two angles shown are vertical angles. They form when you cross two lines. They are opposite one another. Note: They don't have to be vertically up and down in relation to each other. It's possible to have them horizontally side by side like this.

So because they are vertical angles, they are congruent. This means they are equal in measure

x+90 = 4x
x+90-x = 4x-x
90 = 3x
3x = 90
3x/3 = 90/3
x = 30

Therefore the answer is choice C) The value of x is x = 30

We can check it by plugging this into the original equation above
x+90 = 4x
30+90 = 4*30
120 = 120
our answer checks out

3 0
3 years ago
Which of these equations is in POINT-SLOPE form?
goblinko [34]
Y-3=23(x-4) hope this helps
7 0
3 years ago
Two machines are used for filling glass bottles with a soft-drink beverage. The filling process have known standard deviations s
stellarik [79]

Answer:

a. We reject the null hypothesis at the significance level of 0.05

b. The p-value is zero for practical applications

c. (-0.0225, -0.0375)

Step-by-step explanation:

Let the bottles from machine 1 be the first population and the bottles from machine 2 be the second population.  

Then we have n_{1} = 25, \bar{x}_{1} = 2.04, \sigma_{1} = 0.010 and n_{2} = 20, \bar{x}_{2} = 2.07, \sigma_{2} = 0.015. The pooled estimate is given by  

\sigma_{p}^{2} = \frac{(n_{1}-1)\sigma_{1}^{2}+(n_{2}-1)\sigma_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(25-1)(0.010)^{2}+(20-1)(0.015)^{2}}{25+20-2} = 0.0001552

a. We want to test H_{0}: \mu_{1}-\mu_{2} = 0 vs H_{1}: \mu_{1}-\mu_{2} \neq 0 (two-tailed alternative).  

The test statistic is T = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{S_{p}\sqrt{1/n_{1}+1/n_{2}}} and the observed value is t_{0} = \frac{2.04 - 2.07}{(0.01246)(0.3)} = -8.0257. T has a Student's t distribution with 20 + 25 - 2 = 43 df.

The rejection region is given by RR = {t | t < -2.0167 or t > 2.0167} where -2.0167 and 2.0167 are the 2.5th and 97.5th quantiles of the Student's t distribution with 43 df respectively. Because the observed value t_{0} falls inside RR, we reject the null hypothesis at the significance level of 0.05

b. The p-value for this test is given by 2P(T0 (4.359564e-10) because we have a two-tailed alternative. Here T has a t distribution with 43 df.

c. The 95% confidence interval for the true mean difference is given by (if the samples are independent)

(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.05/2}s_{p}\sqrt{\frac{1}{25}+\frac{1}{20}}, i.e.,

-0.03\pm t_{0.025}0.012459\sqrt{\frac{1}{25}+\frac{1}{20}}

where t_{0.025} is the 2.5th quantile of the t distribution with (25+20-2) = 43 degrees of freedom. So

-0.03\pm(2.0167)(0.012459)(0.3), i.e.,

(-0.0225, -0.0375)

8 0
3 years ago
Select the two values of the x that are roots of the given polynomial below. 3x^2+20x-7
lana66690 [7]
3x² <span>+ 20x - 7 =
</span>3x² + 21x - x - 7 =
3x(x+7) - (x+7) = 
(3x-1)(x+7)

3x-1 = 0     or    x+7 = 0
x = -1/3             x=-7

Answer: -7, -1/3.
3 0
4 years ago
Red is a primary color - Violet is not!
Ugo [173]

Answer: ooo

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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