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Using the greatest common factor, it is found that the greatest dimensions each tile can have is of 3 feet.
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- The widths of the walls are of <u>27 feet, 18 feet and 30 feet.</u>
- <u>The tiles must fit the width of each wall</u>, thus, the greatest dimension they can have is the greatest common factor of 27, 18 and 30.
To find their greatest common factor, these numbers must be factored into prime factors simultaneously, that is, only being divided by numbers of which all three are divisible, thus:
27 - 18 - 30|3
9 - 6 - 10
No numbers by which all of 9, 6 and 10 are divisible, thus, gcf(27,18,30) = 3 and the greatest dimensions each tile can have is of 3 feet.
A similar problem is given at brainly.com/question/6032811
Answer:
Step-by-step explanation:
The total number of ways of selecting 3 gems of any kind without replacement is 35 * 34 * 33 = 39270
Now selecting 2 gems from 25 is 25C2
25 C 2 = 25 * 24/2 = 300
Selecting one good gem is 10
Total selection = 300 * 10 = 3000
P(gems) = 3000 / 39270
P(gems) = 300/3927
P(gems) = 100/1309
A walking stick is way longer than a bumble bee
Answer:
144 cloves
Step-by-step explanation:
You separate 42 bulbs of garlic into two groups:one for planting and one for cooking.
We have a ratio of planting to cooking
Planting : Cooking
You will plant 3 bulbs for every 4 bulbs that you will use for cooking.
Hence: 3 : 4
The total of their proportion = 3 + 4 = 7
Hence:
The number of garlic you plant =
3/7 × 42 = 18 bulbs of garlic
The number of garlic you use to cook =
4/7 × 42 = 24 bulbs of garlic
We are also told that:
Each bulb has about 8 cloves. How many cloves of garlic will you plant?
From the calculation above , we know the number of bulbs of garlic been planted
= 18 bulbs.
Hence:.
1 bulb = 8 cloves
18 bulbs = x
x = 8 cloves × 18 bulbs
x = 144 cloves
Therefore, you will plant 144 cloves of garlic
