Can we listen to Iggy Fancy

Virginia purchased 3 packets of flower seeds to plant in her garden. if forty-five flowers bloomed, and each packet contained th

mash [69]

15 is the answer for this

6 0

4 years ago

A chef is going to use a mixture of two brands of Italian dressing. The first brand contains 6% vinegar, and the second brand co

Jobisdone [24]

184 milliliters of the first brand and 46 milliliters of the second brand

Step-by-step explanation:

Step 1:

Let x be the number of milliliters of the first brand in the final mixture

Since the chef requires 230 milliliters, 230 - x would be the milliliters of dressing of the second brand

Step 2:

The first brand contains 6% vinegar, and the second brand contains 11% vinegar

Hence we have,

x * 6/100 + (230-x) * 11/100 = 230 * 7/100

0.06 x + 25.3 - 0.11 x = 16.1

0.05x = 9.2 => x = 184

Hence the 184 milliliters of the first brand is to be used

Step 3 :

Quantity of the second brand to be used is 230 - x = 230 -184 = 46 milliliters.

8 0

4 years ago

In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who p

PolarNik [594]

Using the rules of probability:

P(A∩B)=P(A)+P(B)−P(A∪B) = 22/30 + 18/30 − 27/30 = 13/30 Play both.

3 0

4 years ago

Building A is 464 feet tall and Building B is 321 feet tall. Dale is standing between the buildings. The angle of elevation from

alex41 [277]

Answer:

The distance between the buildings is:

D = 413.3 ft

Step-by-step explanation:

Ok, here we have two triangle rectangles, such that these triangle rectangles share a common vertex which is Dale.

One of the triangles, let's call it triangle A, has the catheti:

Distance between Dale and Building A = d1

Height of Building A = 464 ft

The other triangle (triangle B) has the catheti:

Distance between Dale and Building B = d2

Height of building B = 321ft

We want to find the distance between the buildings, which is equal to d1 + d2.

Then we want to find d1 and d2.

For triangle A:

We know that the angle at the vertex where Dale is standing, is 75°

Then the adjacent cathetus is d1, and the opposite cathetus is the height of building A.

Remember that:

Tan(θ) = (opposite cathetus)/(adjacent cathetus)

Then:

Tan(75°) = (464 ft)/(d1)

d1 = (464 ft)/(Tan(75°)) = 124.3 ft

Now for triangle B, the angle at the vertex where Dale is standing is 48°.

from this vertex, we have d2 as the adjacent cathetus and the height of build B as the opposite cathetus.

Then:

Tan(48°) = 321ft/d2

d2 = (321ft)/(Tan(48°)) = 289ft

Then the distance between the buildings is:

D = d1 + d2 = 124.3 ft + 289ft = 413.3 ft

7 0

3 years ago

HELP MEEEEE PLEASEEEE

loris [4]

Answer:

0.0036 i think this is the answer. I don't really know.

3 0

3 years ago