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Serhud [2]
3 years ago
11

HELP PLEASE QUICK!!!!!

Mathematics
1 answer:
cricket20 [7]3 years ago
7 0

Answer:in what can I help

Step-by-step explanation:

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I need help on this question and I am stuck I have to finish this class by the end of the month
yulyashka [42]
Answer:  The volume is:  " 3.2 mL " . 
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Explanation:
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  "13.2 mL <span>− 10.0 mL = 3.2 mL " .
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6 0
2 years ago
Assortative mating is a nonrandom mating pattern where individuals with similar genotypes and/or phenotypes mate with one anothe
scZoUnD [109]

Answer:

a) P(male=blue or female=blue) = 0.71

b) P(female=blue | male=blue) = 0.68

c) P(female=blue | male=brown) = 0.35

d) P(female=blue | male=green) = 0.31

e) We can conclude that the eye colors of male respondents and their partners are not independent.

Step-by-step explanation:

We are given following information about eye colors of 204 Scandinavian men and their female partners.

              Blue    Brown     Green    Total

Blue        78         23            13          114

Brown     19         23            12          54

Green     11           9             16          36

Total      108       55            41          204

a) What is the probability that a randomly chosen male respondent or his partner has blue eyes?

Using the addition rule of probability,

∵ P(A or B) = P(A) + P(B) - P(A and B)

For the given case,

P(male=blue or female=blue) = P(male=blue) + P(female=blue) - P(male=blue and female=blue)

P(male=blue or female=blue) = 114/204 + 108/204 − 78/204

P(male=blue or female=blue) = 0.71

b) What is the probability that a randomly chosen male respondent with blue eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=blue) = 78/114

P(female=blue | male=blue) = 0.68

c) What is the probability that a randomly chosen male respondent with brown eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=brown) = 19/54

P(female=blue | male=brown) = 0.35

d) What is the probability of a randomly chosen male respondent with green eyes having a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=green) = 11/36

P(female=blue | male=green) = 0.31

e) Does it appear that the eye colors of male respondents and their partners are independent? Explain

If the following relation holds true then we can conclude that the eye colors of male respondents and their partners are independent.

∵ P(B | A) = P(B)

P(female=blue | male=brown) = P(female=blue)

or alternatively, you can also test

P(female=blue | male=green) = P(female=blue)

P(female=blue | male=blue) = P(female=blue)

But

P(female=blue | male=brown) ≠ P(female=blue)

19/54 ≠ 108/204

0.35 ≠ 0.53

Therefore, we can conclude that the eye colors of male respondents and their partners are not independent.

7 0
2 years ago
Given that f(1)=2 and f'(1)=4, find the derivative of f(x)loge(x) when x=1
inessss [21]

Answer:

2

Step-by-step explanation:

loge(x) is ln(x)

f(x) × ln(x)

Differentiate using product law

[ln(x) × f'(x)] + [(1/x) × f(x)]

x = 1

[ln(1) × f'(1)] + [(1/1) × f(1)]

(0 × 4) + (1 × 2)

0 + 2

2

3 0
2 years ago
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wariber [46]
C. an object or a piece of equipment :-)
6 0
3 years ago
Read 2 more answers
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masya89 [10]

Answer:

(8, 6)=(x, y) | (6, 5)= (y, x)

Step-by-step explanation:

Start at the x, and find the value. Next, find the value of y.

You already know the value for y is 6, so next find the value of x, which is 5.

7 0
2 years ago
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