Answer:
See below
Step-by-step explanation:
1)
2)
Equating like terms on both sides:
Solving equations (1) & (2), we find:
A = 5, B = 7
Your neighbor will let you take water from the well on his claim,
charging you $.05 a quart.
If 'x' is the number of quarts you take from his well on Tuesday, then
'y' is the amount of money you owe him before the sun goes down.
Answer:
y^2 +8y + 16
Step-by-step explanation:
6y^2 +2y +5 - (5y^2 -6y -11)
I distribute the minus sign
6y^2 +2y +5 - 5y^2 +6y +11
Then I put them vertical.
6y^2 +2y +5
-5y^2 +6y +11
------------------------
y^2 +8y + 16
This is in standard from since the exponential decreases.
When in doubt C it out man, cant answer it if there aren't any problems to solve
Answer:
We have the system:
x ≤ 7
x ≥ a
Now we want to find the possible values of a such that the system has, at least, one solution.
First, we should look at the value of a where the system has only one solution:
We can write the 2 sets as:
a ≤ x
x ≥ 7
So, writing both together:
a ≤ x ≤ 7
if a is larger than 7, we do not have solutions.
then a = 7 gives:
7 ≤ x ≤ 7
Here the only solution is 7.
Now, if a is smaller than 7, for example 5, we have:
5 ≤ x ≤ 7
Now x can take different values, so we have a lot of solutions.
Then the restrictions for a, such that the system has at least one solution, is:
a ≤ 7.
