Answer:
<em>4.197 N</em>
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Explanation:
current through the wires I = 700 A
distance between wires r = 70 cm = 0.7 m
length of each wire L = 30 m
force per unit length on the wires is given as
=
where u = permeability of vacuum = 1.256 m-kg-
F =
F = = <em>4.197 N</em>
Answer:
1788.402 MJ
Explanation:
Work done = Force (N) x distance (m)
First we have to convert distance into metres:
173.8 x 1000 = 173,800 m
Then plug these values into the equation above:
173,800 x 10290 = 1788402000 J
The reason it's Joules (the unit for energy) is because work done = energy transferred
Now we have to convert Joules into Mega Joules:
1 J = 1/1000000 MJ
1788402000 J = 1788402000/ 1000000 = 1788.402 MJ
Answer: 4.98 m/s
Explanation:
You solve these kinetic energy, potential energy problems by using the fact P.E.+ K.E. = a constant as long as friction is ignored.
PEi = 0 in this case
KEi = ½mVi² = PEf+KEf = mghf + ½mVf²
½1210*8.31² = 1210*9.8*2.26 + ½1210*Vf²
½1210*Vf² = ½1210*8.31² - 1210*9.8*2.26
Vf² = 8.31² - 2*9.8*2.26 = 4.98² so Vf = 4.98m/s
10mph is the acceleration that u are looking for
125 W is the power output of this machine.
Answer:
Explanation:
Power is defined as the amount of work done on the system to move that system from its original state within the given time interval. So it can be determined by the ratio of work done with time interval. As work done is the measure of force required to move a system to a certain distance. Work done is calculated as product of force with displacement.
So in the present case, the force is given as 100 N, the displacement is given as 5 m and the time is given as 4 s, then power is
As Work done = Force acting on the machine × Displacement
So
Power = =125 W
So, 125 W is the power output of this machine.