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2 years ago

Lucia wants to change the motion map shown so that it’s shows uniform circular motion. What change should Lucia make ?

Physics

1 answer:

Andrej [43]2 years ago

7 0

Answer:

The last one - each vector pointing towards the center of the circle must be the same length for uniform circular motion

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A Carnot engine has an efficiency of 83.0% and performs 4500 J of work every cycle. How much energy is discharged to the lower t

ololo11 [35]

We will start by finding the heat in state one through the thermal efficiency or efficiency of a thermal machine is a coefficient or dimensionless ratio calculated as the ratio of the energy produced (in an operating cycle) and the energy supplied to the machine. Mathematically it is the relationship between the work generated and the heat emanated.

So,

$\eta = \frac{W}{Q_1} \rightarrow Q_1 = \frac{W}{\eta}$

$Q_1 = \frac{4500}{0.83}$

$Q_1 = 5421J$

The total change of energy is equivalent to 4500J and this is equal by conservation of energy to the total change in heat. So:

$W = \Delta Q$

$W = Q_1-Q_2$

$4500 = 5421- Q_2$

$Q_2 = 921.68 J$

Therefore the energy which is discharged to the lower temperature reservoir every cicle is 921.7J

6 0

3 years ago

Anser the photo and i'll give brainlest

Maurinko [17]

Answer:

6 b

7 d

Explanation:

6. removed anther

7. recessive

5 0

3 years ago

If you mass 35kg on earth what will your mass be on the moon where gravity is 1/6 that of earths. PLZZZZ HElP NEED ASAP

abruzzese [7]

Answer:

Mass will be same on moon as on Earth but weight will be one-sixth of Earth.

Explanation:

Mass of a body doesn't depend on gravity. Mass is a constant quantity. So, mass on moon will be same as mass on Earth.

But, the weight of a body depends on gravity as weight is given as:

$\textrm{Weight}=\textrm{mass}\times \textrm{acceleration due to gravity}$

Therefore, if $g$ is acceleration due to gravity on Earth, then weight on Earth is, $W_{E}=mg$

Now, gravity on moon is one-sixth of Earth. So, $g_{moon}=\frac{1}{6}g$

Therefore, weight of the body on moon is, $W_{moon}=mg_{moon}=m\times \frac{1}{6}g=\frac{1}{6}mg=\frac{1}{6}W_{E}$

Therefore, a body has same mass both on moon and Earth but weight on moon is one-sixth of the weight on Earth.

4 0

3 years ago

In acceleration time graph curve upward shows _______ acceleration

kondor19780726 [428]

Answer:

rapid

Explanation:

it seems like it.

4 0

3 years ago

Read 2 more answers

A 1200 kg car traveling north at 10 m/s is rear-ended by a 2000 kg truck traveling at 30 m/s. What is the total momentum before

tino4ka555 [31]

Answer:

The total momentum before and after collision is 72000 kg-m/s.

Explanation:

Given that,

Mass of car = 1200 kg

Velocity of car = 10 m/s

Mass of truck = 2000 kg

Velocity of truck = 30 m/s

Using conservation of momentum

The total momentum before the collision is equal to the total momentum after collision.

$m_{1}v_{1}+m_{2}v_{2}=(m_{1}+m_{2})V$

Where, $m_{1}$ =mass of car

$v_{1}$ =velocity of car

$m_{1}$ =mass of truck

$v_{1}$ =velocity of truck

Put the value into the formula

$1200\times10+2000\times30=(1200+2000)V$

$V=\dfrac{1200\times10+2000\times30}{(1200+2000)}$

$V = 22.5\ m/s$

Now, The total momentum before collision is

$P=m_{1}v_{1}+m_{2}v_{2}$

$P=1200\times10+2000\times30$

$P=72000\ kg-m/s$

The total momentum after collision is

$P=(m_{1}+m_{2})v_{2}$

$P=(1200+2000)\times22.5$

$P= 72000 kg-m/s$

Hence, The total momentum before and after collision is 72000 kg-m/s.

4 0

3 years ago