The diagonal fencing will be the hypotenuse of a right triangle with sides 120yds long so:
h=√2(120^2))
h=√28800 yd
And the surrounding fencing will just be four times the side length of 120yds so:
s=480yd
So the total fencing needed is:
f=480+√28800 yards
f≈649.71 yd (to nearest hundredth of a yard) which is
f≈650 yds (to nearest whole yard)
But, I wasn't sure, if they just want the diagonal fencing needed then it is just:
f=√28800
f≈170 yds (to nearest yard)
Answer:
How are this equation and the equation of the line related? They both use the same variable to put it together. What does this relationship mean about any triangle created using this line? They are both put together so it would fit on the graph.
Step-by-step explanation:
The graph shows 1:2, where it's at. And they fit well because the numbers are next to each other. On the y axis, it's 2, right? And on the x axis it's 1, right? So it's 1:2 if that's what you're asking?
Answer:
43
Step-by-step explanation:
Me ayudas por favor es regla de ruffini apretá mi perfil y ve mi pregunta
