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katrin [286]
3 years ago
12

(NEED HELP ASAP! PICTURE IS PROVIDED WITH THE QUESTION.)

Mathematics
1 answer:
yuradex [85]3 years ago
7 0

Answer:

i cant see picture

Step-by-step explanation:

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the RATIO of floor seats to balcony seats in a theaters is 20:1. does this theater have more floor seats or more balcony seats?
GalinKa [24]
Yes, this theater has more floor seats than balcony seats simply because of the ratio. Your answer is actually in the question. For example, if you have 100 floor seats, then according to the ratio you should only have 5 balcony seats.  So yes, there are more floor seats than balcony seats.
3 0
3 years ago
Witch fraction has the same value as 2 3/3
saul85 [17]

Answer: Technically, it would be 9/3, but you can simplify that to 3.

3 0
3 years ago
Read 2 more answers
Please help me I'm a bit stuck on this problem.
bixtya [17]

5 times when all 5 times are up its 7:30 which if 3/4 of a hour which is 45 and is that time4learning?

7 0
3 years ago
An ethanol railroad tariff is a fee charge for shipments of ethanol on public railroads. The Agriculture Marketing Service publi
Stels [109]

Answer:

The appropriate response is "0.9476".

Step-by-step explanation:

The given values are:

Standard deviation,

\sigma=1150

Randomly selected railroad-car shipments,

n = 500

As we know,

⇒ \sigma \bar{x}=\frac{\sigma}{\sqrt{n} }

On substituting the values, we get

⇒      =\frac{1150}{\sqrt{500} }

then,

⇒      =P(-1.94

⇒      =P(Z

On using the table of P, we get

⇒      =0.9738 - 0.0262

⇒      =0.9476

3 0
3 years ago
EasyElectrics supermarket orders light bulbs from suppliers, AA Electronics and AAA Electronics. EasyElectrics purchases 30% of
saw5 [17]

Answer: (a) 0.006

               (b) 0.027

Step-by-step explanation:

Given : P(AA) = 0.3 and P(AAA) = 0.70

Let event that a bulb is defective be denoted by D and not defective be D';

Conditional probabilities given are :

P(D/AA) = 0.02 and P(D/AAA) = 0.03

Thus P(D'/AA) = 1 - 0.02 = 0.98

and P(D'/AAA) = 1 - 0.03 = 0.97

(a) P(bulb from AA and defective) = P ( AA and D)

                                                       = P(AA) x P(D/AA)

                                                       = 0.3 x 0.02 = 0.006

(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)

                         = P(AA) x P(D/AA) + P(AAA) x P(D/AAA)

                         = 0.3(0.02) + 0.70(0.03)

                         = 0.027

3 0
3 years ago
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