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Lostsunrise [7]
3 years ago
14

Help!What does 5x+(-8)= ?

Mathematics
1 answer:
sweet [91]3 years ago
4 0
-3x ,because 5+-8 is obviously -3 then you add the variable x
You might be interested in
What is the solution of the system? Use elimination.
sweet [91]

Answer:

The solutions to the system of the equations by the elimination method will be:

x=2,\:z=-1,\:y=2

Step-by-step explanation:

Given the system of the equations

2x\:+\:2y\:+z\:=\:7

-x-\:y\:+z\:=\:-5

x+3y-4z=12

solving the system of the equations by the elimination method

\begin{bmatrix}2x+2y+z=7\\ -x-y+z=-5\\ x+3y-4z=12\end{bmatrix}

\mathrm{Multiply\:}-x-y+z=-5\mathrm{\:by\:}2\:\mathrm{:}\:\quad \:-2x-2y+2z=-10

\begin{bmatrix}2x+2y+z=7\\ -2x-2y+2z=-10\\ x+3y-4z=12\end{bmatrix}

-2x-2y+2z=-10

+

\underline{2x+2y+z=7}

3z=-3

\begin{bmatrix}2x+2y+z=7\\ 3z=-3\\ x+3y-4z=12\end{bmatrix}

2x+6y-8z=24

-

\underline{2x+2y+z=7}

4y-9z=17

\begin{bmatrix}2x+2y+z=7\\ 3z=-3\\ 4y-9z=17\end{bmatrix}

Rearranging the equations

\begin{bmatrix}2x+2y+z=7\\ 4y-9z=17\\ 3z=-3\end{bmatrix}

solve 3z=-3 for z:

z=-1

\mathrm{For\:}4y-9z=17\mathrm{\:plug\:in\:}z=-1

solve  4y-9\left(-1\right)=17 for y:

4y-9\left(-1\right)=17

4y+9=17

4y=8

y=2

\mathrm{For\:}2x+2y+z=7\mathrm{\:plug\:in\:}z=-1,\:y=2

solve 2x+2\cdot \:2-1=7 for x:

2x+2\cdot \:2-1=7

2x+3=7

2x=4

x=2

Therefore, the solutions to the system of the equations by the elimination method will be:

x=2,\:z=-1,\:y=2

5 0
2 years ago
Help plz......................
stira [4]

Answer:

a)

Step-by-step explanation:

She forgot to multiply 14 with -13

5 0
3 years ago
Read 2 more answers
I need help is it A B C or D
Oksi-84 [34.3K]
The answer would be c.
3 0
2 years ago
Read 2 more answers
a cell phone company offers two different monthly plans.plan a charges $41 for unlimited cell phone minutes plus $0.10 per text
tiny-mole [99]

41+0.10x = 31+0.15x

10 +0.10x=0.15x

10=0.05x

x=10/.05

x= 200 text messages


check 200*0.10 = 20 +41 =61

200*0.15 = 30+31 = 61

 they equal each other so number of texts is 200

6 0
2 years ago
WILL GIVE BRAINLIEST - What is the length of the hypotenuse of the base?<br> *Picture linked below*
Citrus2011 [14]

Answer:

4sqrt(2) cm

Step-by-step explanation:

a^2 + b^2 = c^2

4^2 + 4^2 = c^2

32 = c^2

sqrt(32) = c

c = 4sqrt(2)

6 0
2 years ago
Read 2 more answers
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