5. Write the equation of that is parallel to 2x + 5y - 3 in slope intercept form

Mathematics

1 answer:

zepelin [54]3 years ago

3 0

Answer:

Step-by-step explanation:

5y = -2x + 3

y = -2/5x + 3/5

You might be interested in

HELP URGENT!!!!

Vikki [24]

The equation should be y= -2x+5.

7 0

3 years ago

How would 2.25 be represented as a percent? A. 225% B. 22.5% C. 2.25% D. 0.0225

ivolga24 [154]

Answer:

Step-by-step explanation:

move decimal two places to get percent

2.25 = 225%

6 0

3 years ago

PLZ HELP find the value of x in each of the following x/3-2=6 and x/5+1=5

Aleks [24]

The first one is X = 24 & the second one is x= 20

8 0

2 years ago

Read 2 more answers

How do you find the range of a function?

NISA [10]

<span>For more difficult cases, it may be easier to draw the graph first using the domain if possible and then determine the range graphically.See if you can find the inverse function. The domain of a function's inverse function is equal to that function's range.<span>Check to see if the function repeats.</span></span>

8 0

3 years ago

Find the limit if it exists lim x→0 sqrtx+7-sqrt7 over x

Triss [41]

Answer:

$\frac{1}{ 2\sqrt{7} }$

Step-by-step explanation:

$\lim_{x\to 0} \frac{ \sqrt{x + 7} - \sqrt{7} }{x} \\ \\ = \lim_{x\to 0} \frac{( \sqrt{x + 7} - \sqrt{7}) }{x} \times \frac{( \sqrt{x + 7} + \sqrt{7}) }{( \sqrt{x + 7} + \sqrt{7}) } \\ \\ = \lim_{x\to 0} \frac{( \sqrt{x + 7} )^{2} - (\sqrt{7})^{2} }{x( \sqrt{x + 7} + \sqrt{7})} \\ \\ = \lim_{x\to 0} \frac{( {x + 7} - {7}) }{x( \sqrt{x + 7} + \sqrt{7})} \\ \\ = \lim_{x\to 0} \frac{ {\cancel x}}{\cancel x( \sqrt{x + 7} + \sqrt{7})} \\ \\ = \lim_{x\to 0} \frac{ {1}}{\sqrt{x + 7} + \sqrt{7}} \\ \\ = \frac{1}{ \sqrt{0 + 7} + \sqrt{7} } \\ \\ = \frac{1}{ \sqrt{7} + \sqrt{7} } \\ \\ = \frac{1}{ 2\sqrt{7} }$

6 0

3 years ago