3 years ago

PROBLEM 2 Evaluate 5x – – when x = 4 and y = 2.

Mathematics

1 answer:

krok68 [10]3 years ago

5 0

Answer:

Step-by-step explanation:

1. substitute x for (4)

2. multiply 5(4)

3. The answer is 20

You might be interested in

Find the length of BC

bazaltina [42]

Answer:

BC = 19.78

Step-by-step explanation:

using sin(x) rule

sin(54)= 16/BC

sin(54)=0.80

∴0.80=16/BC (divied both side by 0.80)

BC=16/0.80 =19.78

8 0

3 years ago

Find the midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9)

JulsSmile [24]

The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

<u>Solution:</u>

Given, two points are (-6, 6) and (-3, -9)

We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)$ is given by:

$\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

$\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9$

Plugging in the values in formula, we get,

$\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}$