let's recall that on the IV Quadrant the x/cosine is positive and the y/sine is negative, and of course the hypotenuse is just a radius unit and therefore never negative.
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Answer:
2(x + 1) = 10
x = 4
Step-by-step explanation:
Given:
2(x + 1) = 10
Solution:
Apply Distributive property
A*(B+C) = (A*B) + (A*C)
This means multiply 2 with x and 1
2*(x+1) = (2*x) + (2*1)
2x + 2 = 10
Use Subtraction property of equality
A = B, then A - C = B - C
Subtracting 2 from both sides:
2x + 2 - 2 = 10 - 2
2x = 8 Step 3
Use Division property of equality
It state that if you divide both sides of an equation by same nonzero number then the sides remain equal
Dividing both sides by 2
2x/2 = 8/2
x = 4
This means value of x is 4
Another method to solve this equation is:
2(x+1)=10
Use Distributive property
A*(B+C) = (A*B) + (A*C)
2*(x+1) = (2*x) + (2*1)
2*(x+1) = 2x + 2
Use commutative property
A + (-B) = (-B) + A
2x + 2 + (-2) = 2x + (-2) + 2
2x + 2 + (-2) = 10 + (-2)
2x + 2 - 2 = 10-2
2x = 8
Using division property
AX = B
AX / A = B / A
So
X = B/A
This becomes:
2x = 8
2x = 8.
Divide both sides by 2
2x / 2 = 8 / 2
x = 4
(4,3)
it's asking what you have to do to put it in a scale factor which means like a tree factor
Answer:
The equation of the blue graph is g(x)=(x-3)^{2} +1g(x)=(x−3)
2
+1 . Below is the explanation
Step-by-step explanation:
Given:
The graph of f(x)=x^{2}x
2
To find:
The equation of the transformed graph g(x).
The red graph f(x) is moved right 3 units and up 1 unit to get g(x).
When graph is moved right 3 units , 3 should be subtracted with x.
When graph is moved up 1 unit, 1 is added at the end.
So, our g(x)=(x-3)^{2} +1(x−3)
2
+1
The equation of the blue graph is g(x)=(x-3)^{2} +1g(x)=(x−3)
2
+1
Answer:
1.042g/cm^3
Step-by-step explanation:
