Find the circumference of these circles

Mathematics

1 answer:

EastWind [94]4 years ago

4 0

Formula for Circumference is 2*Pi*radius

1. 18.84 in.
2. 56.52 cm
3. 4.71 ft
4. 25.12 m
5. 37.68 ft.
6. 12.56 yd.
7. 43.96 in
8. 28.26 cm
9. 7.85 m

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6)Factor: x^2+1/3x+1/36

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Answer:

(x+4)(x+9)=0. Your answer would be x=-4 and x=-9. Explanation:: (x+4)(x+9) x times x=x2 x(9)+x(4)=13x 4 times 9=36 = x2+13x+36.(x+4)(x+9)=0. Your answer would be x=-4 and x=-9. Explanation:: (x+4)(x+9) x times x=x2 x(9)+x(4)=13x 4 times 9=36 = x2+13x+36.

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3 years ago

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<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E%7B2%7D%20%2B4x%2B4" id="TexFormula1" title="\sqrt{x^{2} +4x+4" alt="\sqrt{x^{2}

Anna35 [415]

Answer:

Given,

$\sqrt{ {x}^{2} + 4x + 4} - 3 = 0 \\ = > \sqrt{ {x}^{2} + 4x + 4} = 3 \\ = > {( \sqrt{ {x}^{2} + 4x + 4} })^{2} = {3}^{2} \\ = > {x}^{2} + 4x + 4 = 9 \\ = > {x}^{2} + 4x + 4 - 9 = 0 \\ = > {x}^{2} + 4x - 5 = 0 \\ = > {x}^{2} + 5x - x - 5 = 0 \\ = > x(x + 5) - 1(x + 5) = 0 \\ = > (x - 1)(x + 5) = 0 \\ \\ \sf \: either \: x - 1 = 0 \: \: \: \: \\ = > x = 1 \: \: \\ \\ \sf \: or \\ x + 5 = 0 \\ = > x = - 5 \\ \\ \green{ \boxed{ \bf \: \: \: \: \: x = 1 \: \: or \: - 5}}$

But if we put the value of x = 5 then it doesn’t satisfy the equation.

So,

X = 1

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Use the Hinge Theorem or its converse and properties of triangles to write and solve an inequality to describe the restriction o

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Answer:

The inequality is: $3x+2$

The result is: $x>1$

Step-by-step explanation:

1. According to the Hinge Theorem, when you have two triangles and two sides of both triangles are congruent, and the included angle of the first triangle is larger than the included angle of the other triangle, the third side of the first one is longer than the third side of the second one.

2. Keeping this on mind, as you can see in the figure, both triangles has two equal sides, and the included angle of the first one is larger than the angle of the second one:

$38$ °> $30$ °