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NISA [10]
2 years ago
11

How to solve three number questions?

Mathematics
1 answer:
umka2103 [35]2 years ago
8 0
What numbers are u talking about
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Simplify the expression<br> 2(6-8x)+3
Kay [80]
2(6-8x)+3

=12-16x+3
=15-16x
7 0
3 years ago
Please help i will mark brainliest &lt;33
Ugo [173]

Answer:

14.67

Step-by-step explanation:

you added a dot and made this 14.6.7

3 0
2 years ago
Y=5|x+4| ; x= -1 <br> please help
Nostrana [21]

Answer:

15

Step-by-step explanation:

y = 5 l -1 + 4 l

-1 + 4 = 3

3 would not become -3 because positives stay a positive in the inverse operation thing.

5 times 3 is 15

So y is 15

4 0
2 years ago
Read 2 more answers
Given the first and the last terms of a seven-term geometric series with a negative common ratio, what is the sum of all the ter
Aloiza [94]

By using the general formula for a geometric sequence, we will find that the correct option is c: 86

<h3>Working with geometric sequences:</h3>

The general formula for the nth term in a geometric sequence is:

a_n = a_1*r^{n-1}

Where r is the common ratio of the geometric sequence here we know that:

  • a₁ = 2
  • a₇ = 128
  • r is negative.

Replacing the first two in the general formula we get:

a_7 = a_1*r^6\\&#10;\\&#10;128 = 2*r^6\\\\&#10;&#10;128/2 = 64 = r^6\\&#10;&#10;\\&#10;&#10;-64^{1/6} = r = -2

Where we took the negative solution for the root. Now that we know the common ratio we can find the other terms:

a_1  = 2\\&#10;a_2 = 2*(-2) = -4\\&#10;a_3 = -4*(-2) = 8\\&#10;a_4 = 8*(-2) = -16\\&#10;a_5 = -16*(-2) = 32\\&#10;a_6 = 32*(-2) = -64\\&#10;a_7 = -64*(-2) = 128

The sum gives:

2 - 4 + 8 - 16 + 32 - 64 + 128 = 86

So the correct option is c.

If you want to learn more about geometric sequences, you can read:

brainly.com/question/9300199

7 0
2 years ago
HELPPP I NEED TO GET THIS DONE BY TONIGHT DOES ANYONE KNOW HOW TO WRITE THIS OUT IM CONFUSED THE PIC IS “QUESTION 1” btw
Oxana [17]

Answer:

rsm lol good luck with that

Step-by-step explanation:

im stuck on the same one any helpers?

3 0
2 years ago
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