24a²-30 at 9 Solve please
1 answer:
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Answer:
A ) Not orthogonal to each other
B) 50i + 40j + 105k
C) The tensor product is attached below
D ) The value of X = F.X is attached below
Step-by-step explanation:
attached below is the detailed solution of the above problem
A) for the vectors ( u ) and ( v ) to be orthogonal to each other [ U.V has to be = 0 ] but in this scenario U.V = 4 hence they are not orthogonal to each other
b) The vector normal to plane is gotten by : U x V
= 50i + 40j + 105k
Answer:
Step-by-step explanation:
We want to find the distance between two points, so the following formula is used.
Where (x₁, y₁) and (x₂, y₂) are the points we are finding the distance between.
We are given the points (-2, -1) and (3,2). If we match the corresponding value and variable we see that:
- x₁= -2
- y₁= -1
- x₂= 3
- y₂= 2
Substitute the values into the formula.
Solve the parentheses.
- -2 -3 = -5
- 2--1 = 2+ 1 = 3
Solve the exponents.
- (-5)²= -5*-5= 25
- (3)²= 3*3=9
Add.
This radical cannot be simplified, so the distance between the two points is <u>√34</u> and <u>choice 3 </u> is correct.
The expression that models the length of the second leg of the triangle is <u>2x - 3.</u>
<u><em>Recall</em></u>:
The area of a triangle =
<em><u>Given</u></em>:
Area of triangle =
Length of one of the legs = 3x + 1
Therefore, it means that multiplying both legs should give us:
To find the expression that models the other leg, divide by 3x + 1:
- <em>Thus</em>:
- Factorize the numerator
- Simplify
Therefore, the expression that models the length of the second leg of the triangle is <u>2x - 3.</u>
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