Answer:
growth rate = 0.1733 per day, or 17.33% per day
Step-by-step explanation:
Since the doubling time is 4 days, the growth factor over a period of t days is ...
2^(t/4)
Then the growth factor for 1 day is
2^(1/4) ≈ 1.189207
The instantaneous growth rate is the natural log of this:
ln(1.189207) ≈ 0.1733 . . . per day
Answer:
Step-by-step explanation:
- Start time = 2 PM
- Speed of the first train = 50 mph
- Speed of the second train = 60 mph
- Trains head same direction
- The second train spends 3 hour less time than the first but both take same distance
<u>Let the time in travel for the first train be x, then we have equation for distance:</u>
- 50x = 60(x - 3)
- 50x = 60x - 180
- 60x - 50x = 180
- 10x = 180
- x = 18 hours
<u>Time when the second train caches up the first one:</u>
- 2 PM + 18 hours = 8 AM next day
Answer:
Expansion for there will be 9 terms.
(a+b) ^n =nco a^n b^o+ nc1 a^(n-1) b^1+nc2 a^(n-2) b^2+nc3 a(n-3) b^3+nc4 a^(n-4) b^4+...........................ncn a^o b^n.
5th term of (2x+y)^8 = ?
5th term is nC4 a^(n-4) b^4
a=2x, b=y, n=8
therefore 8C4 (2x)^(8-4) (y)^4
8!/((8-4)! 4!) (2x)^4 y^4
40320/576 (16 x^4 ) (y^4)
70 (16x^4)(y^4)
1120 X^4 Y^4
Step-by-step explanation:
Answer:
(a) 10.
Step-by-step explanation:
When x = 2 x + x(x^x) =
2 + 2(2^2)
= 2 + 2*4
= 2 + 8
= 10.
