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3 years ago

What's the algebraic expression for 5,9,13,17,21

1 answer:

5 0

1,5,9,13,17,21,25,29..., 4n+1
in general terms of an arithmetic sequence with the first term A0 and common differences d,

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( 4 − 3 ) 2 ; 1 6 2 + 9

Butoxors [25]

do I just have to find the sum?

8 0

2 years ago

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Can someone please help me!!!

astra-53 [7]

Answer:

H. 260

Step-by-step explanation:

We'll begin this problem by first figuring out how many students will be able to sit at the first fourteen tables.

14 tables * 14 students = total students

196 = total students ( for those fourteen tables)

Now we also know that sixteen students can sit on the rest of the cafeteria tables.

We need to find the number of tables can hold sixteen students.

To do this, we'll lead with a simple equation:

18 tables total - 14 tables = # of remaining tables

4 = # of remaining tables

Now we're going to do the same thing we did with the original tables:

4 tables * 16 students = total students

64 = total students

Finally, we add both of the tables max values together:

64 + 196 = 260

7 0

3 years ago

Find the circumference

AleksAgata [21]

12 times 3.14 = 37.68 CM
C=D x 3.14

5 0

3 years ago

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(3)/(2x+3)=(2)/(10x+4)

RoseWind [281]

Answer:

x = -3/13

Step-by-step explanation:

cross multiply

4x + 6 = 30x + 12

combine like terms

-6 = 26x

x = -6/26 = -3/13

7 0

3 years ago

need help. solve for y. try factoring first if not possible or difficult use quadratic formula. y²-6y+6=0

lbvjy [14]

$y^2-6y+6=0\\ \\a=1 , \ b=-6, \ c=6 \\ \\\Delta =b^2-4ac = (-6)^2 -4\cdot1\cdot6 = 36-24=12\\ \\\sqrt{\Delta }= \sqrt{12}=\sqrt{4\cdot 3}=2\sqrt{3} \\ \\x_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{6-2\sqrt{3}}{2 }=\frac{2( 3- \sqrt{3})}{2}= 3- \sqrt{3}$

$x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{6+2\sqrt{3}}{2 }=\frac{2( 3+ \sqrt{3})}{2}= 3+ \sqrt{3}$

3 0

3 years ago

Read 2 more answers