So for order of operations you start inside the parentheses and in order to add the insides you will need a common denominator which would be 15 on the bottom. So for 2/5 it would be 6/15 and for 11/3 would be 55/15 and then added together it would be 61/15. so then you would multiply and get 15(61/15). the 15 in the numerator will cancel with the denominator leaving only 61 and then the final step would be adding the 3 to 61 and the final answer will be 64
Answer: I believe it’s y=x+7
Step-by-step explanation:
Lawrence's is the correct answer. he put 3 plates on each box in both situations
Answer:
c) 2
d) 0.96
Step-by-step explanation:
We are given the following in the question:
a) probability density function.
![\displaystyle\int^{\infty}_{\infty}f(x) dx = 1\\\\\displaystyle\int^{\infty}_{-\infty}2x^{-3}dx = 1\\\\\displaystyle\int^{\infty}_{1}2x^{-3}dx\\\\\Rightarrow \big[-x^{-2}\big]^{\infty}_1\\\\\Rightarrow -(0-1) = 1](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cint%5E%7B%5Cinfty%7D_%7B%5Cinfty%7Df%28x%29%20dx%20%3D%201%5C%5C%5C%5C%5Cdisplaystyle%5Cint%5E%7B%5Cinfty%7D_%7B-%5Cinfty%7D2x%5E%7B-3%7Ddx%20%3D%201%5C%5C%5C%5C%5Cdisplaystyle%5Cint%5E%7B%5Cinfty%7D_%7B1%7D2x%5E%7B-3%7Ddx%5C%5C%5C%5C%5CRightarrow%20%5Cbig%5B-x%5E%7B-2%7D%5Cbig%5D%5E%7B%5Cinfty%7D_1%5C%5C%5C%5C%5CRightarrow%20-%280-1%29%20%3D%201)
Thus, it is a probability density function.
b) cumulative distribution function.
c) mean of the distribution
d) probability that the size of random particle will be less than 5 micrometers
Answer:
Step-by-step explanation:
<u>Given:</u>
<u>Solve for </u>
<u> in the 1st equation:</u>
<u>Substitute the value of </u><u> into the 2nd equation and solve for </u>
<u>:</u>
<u>Substitute the value of </u><u> into the 3rd equation and solve for </u>
<u>:</u>
<u>Plug </u><u> into the solved expression for </u><u> and evaluate to solve for </u><u>:</u>
<u>Plug </u><u> into the solved expression for </u><u> and evaluate to solve for </u><u>:</u>
Therefore:
