Answer:
Extrasolar planets are very dim light sources compared to their stars. At visible wavelengths, they generally have less than a millionth of the brightness of their parent star. It is extremely difficult to detect this type of dim light source, and in addition, the parent star has dazzling light that almost makes it impossible.
Answer:
Drag force=1/2Cd*Area*density*V^2
A=240 ft^2
cd=0.75
Drage force=675 lbs
Explanation:
Given that,
Radius of the circular loop, r = 3.5 cm = 0.035 m
(a) During a 0.12-s time interval, the magnitude of the field increases uniformly from 0.2 T to 0.5 T. Due to the change in the magnetic field, an emf will induced in it. The magnitude of induced emf is given by :
So, the magnitude of the emf induced in the loop during the time interval is 
.
(b) The negative sign shows that the direction of induced emf in the loop is in anitclockwise direction.
"Nitrogen gas" makes up 75% (approx. 78%) of the earth's atmosphere
Hope this helps!
The force that must be exerted on the outside wheel to lift the anchor at constant speed is 6.925 x 10⁵ N.
<h3>Force exerted outside the wheel</h3>
The force exerted on the outside of the wheel can be determined by applying the principle of conservation of angular momentum as shown below.
∑τ = 0
- Let the distance traveled by the load = 1.5 m
- Let the radius of the wheel or position of the force = 0.45 m
∑τ = R(mg) - r(F)
rF = R(mg)
0.45F = 1.5(21,200 x 9.8)
F = 6.925 x 10⁵ N.
Thus, the force that must be exerted on the outside wheel to lift the anchor at constant speed is 6.925 x 10⁵ N.
Learn more about angular momentum here: brainly.com/question/7538238
