D. The answer is D because any other scenario is possible. For example, in A, John could very easily put the planets in order. In problem B, he could draw some planets bigger than others. On C, he could color the planets on a different color. He can not hovever, move the planets
The horizontal speed has no effect on how long it takes to reach the ground.
A bullet shot from a gun and a bullet dropped from the front end of the gun
at the same time as the shot both hit the ground at the same time.
The number that counts is the height from which it fell . . . the 1.25 m.
I'll use this very useful formula:
Distance of free fall,
starting from rest = (1/2) · (gravity) · (time)²
1.25 m = (1/2) · (9.8 m/s²) · (time)²
Divide each side
by 4.9 m/s² : 1.25 m / 4.9 m/s² = time²
0.2551 sec² = time²
Square root each side: 0.505 sec = time
It looks like the correct choice is approximately 'A'. (rounded)
Answer:
I. Stopping acceleration = 6 m/s²
II. Stopping distance, S = 75 meters
Explanation:
Given the following data;
Final velocity = 30 m/s
Time = 5 seconds
To find the stopping acceleration;
Mathematically, acceleration is given by the equation;

Substituting into the equation;
Acceleration = 6 m/s²
II. To find the stopping distance, we would use the third equation of motion;
Where;
V represents the final velocity measured in meter per seconds.
U represents the initial velocity measured in meter per seconds.
a represents acceleration measured in meters per seconds square.
Substituting into the equation, we have;
30² = 0² + 2*6*S
900 = 12S
S = 900/12
S = 75 meters
Answer:
L = mp*v₀*(ms*D) / (ms + mp)
Explanation:
Given info
ms = mass of the hockey stick
uis = 0 (initial speed of the hockey stick before the collision)
xis = D (initial position of center of mass of the hockey stick before the collision)
mp = mass of the puck
uip = v₀ (initial speed of the puck before the collision)
xip = 0 (initial position of center of mass of the puck before the collision)
If we apply
Ycm = (ms*xis + mp*xip) / (ms + mp)
⇒ Ycm = (ms*D + mp*0) / (ms + mp)
⇒ Ycm = (ms*D) / (ms + mp)
Now, we can apply the equation
L = m*v*R
where m = mp
v = v₀
R = Ycm
then we have
L = mp*v₀*(ms*D) / (ms + mp)