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Sonbull [250]
3 years ago
7

Why does paper become wet intermolecular forces

Physics
1 answer:
mel-nik [20]3 years ago
7 0
From the pulp and paper industry, it is known as bulking state of polymer (swelling of polymer). The paper is made mainly from zellulose, and the zellulose is a amorphous-crystalline polymer. In the water there is restricted intercrystalline swelling, when the macromolecules of zellulose enlarge the distance between each other, and the molecules of water fill this space. As the result, swelled zellulose loses its strength and can be easily teared, so because that. When that water hits the paper, it tears more easily than anything because of those intermolecular forces.
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If someone looks far enough into space, they should be able to see the beginning of the universe true of false
kodGreya [7K]
The answer is no, it would be impossible to see the beginning of the universe
8 0
2 years ago
PLEASE HELP! SCIENCE QUESTION
Nikolay [14]

The answer is:

A) Light wave changes direction.

Here is why:

In refraction, the<u> light bends or changes direction</u> when it passes through one medium to another. The change happens because the speed of light is different depending on the medium it passes through because the density of the medium is different.

Another difference would be the angle of incidence. In reflection the angle of incidence is equal to the angle of reflection but in refraction, they are not the same.

7 0
3 years ago
A block is given a very brief push up a 20.0 degree frictionless incline to give it an initial speed of 12.0 m/s.(a) How far alo
Orlov [11]

Explanation:

(a)   Net force acting on the block is as follows.

           F_{net} = -mg Sin (\theta)

or,           ma = -mg Sin (\theta)[/tex]

                 a = -g Sin (\theta)

                    = -9.8 \times Sin (20^{o})

                    = -3.35 m/s^{2}

According to the kinematic equation of motion,

             v^{2} - v^{2}_{o} = 2as

Distance traveled by the block before stopping is as follows.

     s = \frac{v^{2} - v^{2}_{o}}{2a}

        = \frac{(0)^{2} - (12.0)^{2}_{o}}{2 \times -3.35}

        = 21.5 m

According to the kinematic equation of motion,

               v = v_{o} + at

      0 = 12.0 m/s + \frac{1}{2} \times -3.35 m/s^{2} \times t

   t_{1} = 7.16 sec

Therefore, before coming to rest the surface of the plane will slide the box till 7.16 sec.

(b)    When the block is moving down the inline then net force acting on the block is as follows.

                 F_{net} = -mg Sin (\theta)

                ma = mg Sin (\theta)

                    a = g Sin (\theta)

                       = 9.8 m/s^{2} \times Sin (20^{o})

                       = 3.35 m/s^{2}

Kinematics equation of the motion is as follows.

                   s = v_{o}t + \frac{1}{2}at^{2}

      21.5 m = 0 + \frac{1}{2} \times 3.35 m/s^{2} \times t^{2}

     t_{2} = \sqrt{\frac{2 \times 21.5 m}{3.35 m/s^{2}}}

             = 3.58 sec

Hence, total time taken by the block to return to its starting position is as follows.

               t = t_{1} + t_{2}

                 = 7.16 sec + 3.58 sec

                 = 10.7 sec

Thus, we can conclude that 10.7 sec time it take to return to its starting position.

3 0
3 years ago
Please help me thank you <br> Fr+Cl=FeCl3
docker41 [41]
Fe+3Cl->FeCl3

Wish you always happy
5 0
3 years ago
A liquid of density 1390 kg/m 3 flows steadily through a pipe of varying diameter and height. At Location 1 along the pipe, the
Aloiza [94]

Answer:

The difference of power is

ΔP = 172.767 kPa

Explanation:

ρ = 1390 kg / m³

v = 9.63 m/s

d₁ = 10.1 cm , d₂ = 15.3 cm

Δz = 8.85 m

To find the difference ΔP between the fluid pressure at locations 2 and the fluid pressure at location 1

ΔP = ρ * g * Z + ¹/₂ * ρ * v² * ( 1 - (d₁ / d₂)⁴ )

ΔP = 1390 kg / m³ * 9.8 m/s² * 8.85 m + 0.5 * 1390 kg / m³ *(9.63 m /s)² * (1 - (0.101 m / 0.153 m )⁴ )

ΔP = 172.767 x 10 ³ Pa

ΔP = 172.767 kPa

6 0
2 years ago
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