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Ludmilka [50]
2 years ago
10

A bucket is full of oil. The total mass of the bucket of oil is 5.4kg and the gravitational field strength is 10N\kg. Calculate

the total weight of the bucket of oil
Physics
1 answer:
larisa86 [58]2 years ago
8 0

This question involves the concepts of gravitational field strength and mass of the object.

The total weight of the bucket of oil is "54 N".

The gravitational field strength is defined as the weight of an object in the gravitational field per unit mass of the object. Hence, mathematically it can be written as follows:

S-\frac{W}{m}\\\\W= (S )(m)

where,

W = weight of the bucket of oil = ?

S = gravitational field strength = 10 N/kg

m = mass od the bucket of oil = 5.4 kg

Therefore,

W=(10\ N/kg)(5.4\ kg)\\

<u>W = 54 N</u>

<u></u>

Learn more about gravitational field intensity here:

brainly.com/question/12313730?referrer=searchResults

The attached picture illustrates the concept of gravitational field intensity.

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If all of the forces acting on an object are balanced, then:
kondaur [170]

A. the direction the object is moving in will not change.

B. the acceleration of the object will be 0 m/s2

Explanation:

We can answer this problem by using Newton's second law of motion:

\sum F = ma

where

\sum F is the net force acting on an object

m is the mass of the object

a is its acceleration

In this problem, all the forces acting on the object are balanced, therefore the net force is zero:

\sum F=0

which means that also the acceleration is zero:

a=0

Acceleration is equal to the rate of change of velocity: therefore, zero acceleration means that the velocity of the object does not change. We can now analyze the given statements:

A. the direction the object is moving in will not change.  --> TRUE, because the velocity is not changing.

B. the acceleration of the object will be 0 m/s2  --> TRUE, as we stated above

c. the object will not be in motion.  --> FALSE: we just know that its velocity is constant, but it can be different from zero

D. the velocity of the object will be 0 m/s. --> FALSE, for the same reason stated in C

Learn more about Newton's second law of motion:

brainly.com/question/3820012

#LearnwithBrainly

3 0
3 years ago
Knowing Newton’s 2nd Law, how would you rearrange it to solve for acceleration.
AysviL [449]

Answer:

Force / mass

Explanation:

Divide mass on both sides to get acceleration by itself leaving you with mass below force hence divide force by mass

8 0
3 years ago
Read 2 more answers
When an object moves in uniform circular motion, the direction of its acceleration is?
Harrizon [31]
Clock wise idk i think you should double check my answer

7 0
3 years ago
2.)
Oduvanchick [21]

Answer:

-22.7 m/s^2

Explanation:

This is a uniformly accelerated motion, so we can determine the deceleration of the car by using a suvat equation:

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance covered

For the car in this problem,

u = 27.8 m/s

v = 0

s = 17 m

Solving for a, we find the acceleration:

a=\frac{v^2-u^2}{2s}=\frac{0-27.8^2}{2(17)}=-22.7 m/s^2

4 0
3 years ago
A passenger compartment of a rotating amusement park ride contains a bench on which a book of mass
Basile [38]

a) 120 s

b) v = 0.052R [m/s]

Explanation:

a)

The period of a revolution in a simple harmonic motion is the time taken for the object in motion to complete one cycle (in this case, the time taken to complete one revolution).

The graph of the problem is missing, find it in attachment.

To find the period of revolution of the book, we have to find the time between two consecutive points of the graph that have exactly the same shape, which correspond to two points in which the book is located at the same position.

The first point we take is t = 0, when the position of the book is x = 0.

Then, the next point with same shape is at t = 120 s, where the book returns at x = 0 m.

Therefore, the period is

T = 120 s - 0 s = 120 s

b)

The tangential speed of the book is given by the ratio between the distance covered during one revolution, which is the perimeter of the wheel, and the time taken, which is the period.

The perimeter of the wheel is:

L=2\pi R

where R is the radius of the wheel.

The period of revolution is:

T=120 s

Therefore, the tangential speed of the book is:

v=\frac{L}{T}=\frac{2\pi R}{120}=0.052R

8 0
3 years ago
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