The correct Standard Form of the equation y=3/2x+3

You purchased a new car for 17,999 in the year 2015. It is now 2020 and you want to sell your car for a fair price. If your car

salantis [7]

Answer:

$7,986.25

Step-by-step explanation:

We can use the following formula to solve:

$A=P(1-r)^t$

P = principal value

r = rate (decimal)

t = time (years)

First, change 15% into a decimal:

15% -> $\frac{15}{100}$ -> 0.15

Since 2015 and 2020 are 5 years apart, we will use 5 for t. Now, plug the values into the equation:

$A=17,999(1-0.15)^5$

$A=7,986.25$

Your car would be worth $7,986.25

8 0

3 years ago

5+4+2 (-3)+7+(-5) equals to?

Cerrena [4.2K]

5+4+2(-3)+7+(-5)
or
5+4+2-3+7+(-5)?

7 0

3 years ago

Read 2 more answers

Need help asap thank you

Angelina_Jolie [31]

Answer:

D is 107 and E is 38

Step-by-step explanation:

20x+40=180

20x=140

X=140/20

x=7

M<A=5(7)+3

38

m<a=m<e

15(7)+2

107

m<b=m<d

5 0

3 years ago

BRAINLIEST ✨

inna [77]

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, or

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, or

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, or

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.Check: (2 + 2/3), (2 + 3*2/3), (2 + 6*2/3)

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.Check: (2 + 2/3), (2 + 3*2/3), (2 + 6*2/3)= 8/3, 4, 6

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.Check: (2 + 2/3), (2 + 3*2/3), (2 + 6*2/3)= 8/3, 4, 6Common ratio: 4/(8/3) = 3/2 same as 6/4 = 3/2. Correct.

Step-by-step explanation:

Am I right? just commet if I'm wrong

then TANKYOU>^_^<!

7 0

2 years ago

Pleas help as fast as possibeleeelelelellelele

Mademuasel [1]

Answer:

Step-by-step explanation:

3 0

2 years ago