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2 years ago

6

Please help me answer this question ASAP

1 answer:

Mars2501 [29]2 years ago

6 0

Answer:

60 km

Step-by-step explanation:

the line is constant around 3

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PLEASE PLEASE HELP ME NO DOWNLOADABLE FILES<br><br> How many solutions <br> y=2x^2+9x

lisabon 2012 [21]

Answer:

There's going to be 2 solutions

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Please answer please

Murrr4er [49]

<BAC = <DEC = 30°

<BCA = <DCE = 70°

<CDE (or m<D) = 180° - <DEC - <DCE

<CDE = 180° - 30° - 70°

<CDE = 80°

The number that belongs in the green box is 80

3 0

3 years ago

Θ is an acute angle and cosecant theta equals nine halves commacscθ= 9 2, find secant ((pi over 2) minus theta) .sec π 2−θ. do n

Ronch [10]

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8 0

3 years ago

If one zero of the polynomial (a^2+9)x^2+13x+6a is the reciprocal of the other, find the value of a.

mihalych1998 [28]

Answer: a^2x^2+9x^2+13x+6a

Step-by-step explanation:

(a^2+9) x^2+ 13x +6a

x^2(a^2+9)+13x+6a

Expand:x^2(a^2+9): a^2 x^2+9^2

x^2 a^2 +x^2*9

a^2 x^2+9x^2

a^2 x^2+9x^2+13x+6a

5 0

2 years ago

A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri

GuDViN [60]

Answer:

1. $\frac{dy}{dt}=ky$

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

$\frac{dy}{dt}$ =Number of bacteria per unit time

$\frac{dy}{dt}\proportional y$

$\frac{dy}{dt}=ky$

Where k=Proportionality constant

2. $\frac{dy}{y}=kdt$ ,y'(0)=100

Integrating on both sides then, we get

$lny=kt+C$

We have y(0)=200

Substitute the values then , we get

$ln 200=k(0)+C$

$C=ln 200$

Substitute the value of C then we get

$ln y=kt+ln 200$

$ln y-ln200=kt$

$ln\frac{y}{200}=kt$

$\frac{y}{200}=e^{kt}$

$y=200e^{kt}$

Differentiate w.r.t

$y'=200ke^{kt}$

Substitute the given condition then, we get

$100=200ke^{0}=200 \;because \;e^0=1$

$k=\frac{100}{200}=\frac{1}{2}$

$y=200e^{\frac{t}{2}}$

Substitute t=2

Then, we get $y=200e^{\frac{2}{2}}=200e$

$y=200(2.718)=543.6=543.6$

e=2.718

Hence, the number of bacteria after 2 hours=543.6

4 0

3 years ago