Question

How many real number solutions does the equation have. Y=3x^2-5x-5

Answer 1

Answer:

2

Step-by-step explanation:

To find how many real solution a quadratic equation has, we just need to find the value of its discriminant. If the discriminant is zero, the quadratic only has one real solution; if the discriminant is positive, the quadratic has two real solution; if the discriminate is negative, the quadratic doesn't has any real solutions.

The discriminant of a quadratic equation of the form $ax^2+bx+c$ is given by: $b^2-4ac$

We know from our quadratic that $a=3$, $b=-5$, and $c=-5$.

Replacing values:

$(-5)^2-4(3)(-5)$

$25+60$

$85$

Since the discriminant is positive, we can conclude that our quadratic equation has two real solutions.