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PtichkaEL [24]
3 years ago
7

What's the unit rate for 219 heartbeats in 3 minutes?

Mathematics
2 answers:
olga2289 [7]3 years ago
7 0
Easy
219/3=73Beats per minute
Tomtit [17]3 years ago
3 0

Answer:

60

Step-by-step explanation:

This is very simple.

We just have to divide 180 by 3

When we do this we would get a final result of 60

Hope thiss was helpfull!

                                                                                                                   Dylan K.

     

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An automobile manufacturer is concerned about a possible recall of its best selling four-door sedan. If there was a recall there
goldfiish [28.3K]

Complete question is;

An automobile manufacturer is concerned about a possible recall of its best - selling four-door sedan. If there were a recall, there is a probability of 0.25 of a defect in the brake system, 0.18 of a defect in the transmission, 0.17 of a defect in the fuel system, and 0.40 of a defect in some other area.

(a) What is the probability that the defect is the brakes or the fueling system if the probability of defects in both systems simultaneously is 0.15?

(b) What is the probability that there are no defects in either the brakes or the fueling system?

Answer:

A) 0.27

B) 0.73

Step-by-step explanation:

Let B denote that there is a defect in the break system

Let T demote that there is a defect in transmission

Let F denote that there is a defect in the fuel system.

Let P denote that there is a defect in some other area.

Now, we are given;

P(B) = 0.25

P(T) = 0.18

P(F) = 0.17

P(O) = 0.40

A) We are given that probability of defects in both brakes and the fueling system simultaneously is 0.15.

Thus, it means; P(B ⋂ F) = 0.15

Now, we want to find the probability that the defect is the brakes or the fueling system. This is expressed as;

P(B ⋃ F) = P(B) + P(F) - P(B ⋂ F)

Plugging in the relevant values to give;

P(B ⋃ F) = 0.25 + 0.17 - 0.15

P(B ⋃ F) = 0.27

B) We want to find the probability that there are no defects in either the brakes or the fueling system.

This is expressed as;

P(B' ⋃ F') = 1 - P(B ⋃ F)

Plugging in relevant value;

P(B' ⋃ F') = 1 - 0.27

P(B' ⋃ F') = 0.73

7 0
3 years ago
Which of the following points lies in Quadrant II?
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The answer is d. (-3,8.)

6 0
3 years ago
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pickupchik [31]
100x3=300
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3 years ago
A computer chess game and a human chess champion are evenly matched. They play twelve games. Find probabilities for the followin
sleet_krkn [62]

Answer:

The probability that they each win six games is 0.225.      

Step-by-step explanation:

Given : A computer chess game and a human chess champion are evenly matched. They play twelve games.

To find : The probability that they each win six games?

Solution :

Applying binomial distribution,

Here n=12 and p=0.5

P(X=k)=\frac{n!}{k!(n-k)!}\times p^k\times (1-p)^{n-k}

The probability that they each win six games is k=6.

P(X=6)=\frac{12!}{6!(12-6)!}\times 0.5^6\times (1-0.5)^{12-6}

P(X=6)=\frac{12\times 11\times 10\times 9\times 8\times 7\times 6!}{6\times 5\times 4\times 3\times 2\times 6!}\times 0.015625\times 0.015625

P(X=6)=11\times 2\times 3\times 2\times 7\times 0.015625\times 0.015625

P(X=6)=0.225

Therefore, The probability that they each win six games is 0.225.

3 0
3 years ago
Which Inequality is represented by the number line graph?
USPshnik [31]

Answer:

option C is your right answer

Step-by-step explanation:

have a nice day!!

8 0
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