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Setler [38]
3 years ago
5

Which strategy best explains how to solve this problem? Colin is preparing for a marathon by running in his neighborhood. The fi

rst week, he runs one block. The next week, he runs twice as many blocks as the first week (2 blocks). Each week, he plans to run twice as many blocks as he ran the week before. How many blocks will Colin run by the end of the sixth week? A. Use objects to model the problem. Put out 1 chip to represent the blocks run in week one. Put out twice that amount for week two. Put out twice that amount (from week two) for week three. Do this 3 more times, putting out twice the amount from the previous week each time. B. Make a table. In the first row, write first week - 2 blocks. In the next row, write second week - 4 blocks. In the third row, write third week -6 blocks. Continue this pattern for three more rows. C. Write a number sentence. (1 + 2) × 6 = x Add the number of blocks run in the first and 2nd week. Then multiply the sum by the number of weeks (6).
Mathematics
1 answer:
Aneli [31]3 years ago
7 0
I would say the answer is B. 
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The Cowboys High School Band Boosters are selling candy bars and chips at the basketball tournament to raise money for their ban
masya89 [10]

Answer:

They have 425 candy bars ready to sell.

Step-by-step explanation:

Let,

x be the number of candy bars ready to sell

y be the number of chips ready to sell

According to given statement;

x+y=575     Eqn 1

x+0.5y= 500     Eqn 2

Subtracting Eqn 2 from Eqn 1

(x+y)-(x+0.5y)=575-500

x+y-x-0.5y=75

0.5y = 75

Dividing both sides by 0.5

\frac{0.5y}{0.5}=\frac{75}{0.5}\\y=150

Putting y=150 in Eqn 1

x+150 = 575

x = 575-150

x = 425

Hence,

They have 425 candy bars ready to sell.

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3 years ago
Simplify the expression 35e^9/5e^8
erastovalidia [21]

\frac{35e {}^{9} }{5 {e}^{8} }  \ \\  \\   \frac{7e {}^{9} }{e {}^{8} }  \\  \\  \\  = 7e

Step By Step Explanation:

  • Reduce: Reduce the fraction with 5
  • Simplify: Simplify the expression

Alternate Forms:

  • 19.02797

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Svetach [21]

Answer:

4, 12, 16 (respectively)

Step-by-step explanation:

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HELP ME ANSWER THIS QUESTION QUICKLY BEFORE KATIE REMOVES IT FOR SOME RANDOM REASON.
Marrrta [24]

Answer:

\vec{BC}=2b - 4a

\vec{XY}=a+ b

\vec {CY}=a - 2b

Step-by-step explanation:

By the triangular law of vector addition:

\vec {CY}=\vec {CA}+ \vec{AY}

\vec {CY}=a - 2b

We have that;

\frac{YB}{AY} =  \frac{3}{1}

\implies YB = 3 AY \\  \vec {YB}  = 3  \vec {AY}

\vec {YB}  = 3 a

From triangle ABC,

\vec{BC}=\vec{BA}+\vec{AC} \\ \vec{BC}=2b - 4a

Again from triangle XYB

\vec{XY}=\vec{YB}+\vec{BX} \\

\vec{XY}=\vec{YB}+ \frac{1}{2} \vec{BC}

\vec{XY}=3a+ \frac{1}{2} (2b - 4a)

\vec{XY}=3a+ b - 2a \\ \vec{XY}=a+ b

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Answer:

See the files.

Step-by-step explanation

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