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Setler [38]
3 years ago
5

Which strategy best explains how to solve this problem? Colin is preparing for a marathon by running in his neighborhood. The fi

rst week, he runs one block. The next week, he runs twice as many blocks as the first week (2 blocks). Each week, he plans to run twice as many blocks as he ran the week before. How many blocks will Colin run by the end of the sixth week? A. Use objects to model the problem. Put out 1 chip to represent the blocks run in week one. Put out twice that amount for week two. Put out twice that amount (from week two) for week three. Do this 3 more times, putting out twice the amount from the previous week each time. B. Make a table. In the first row, write first week - 2 blocks. In the next row, write second week - 4 blocks. In the third row, write third week -6 blocks. Continue this pattern for three more rows. C. Write a number sentence. (1 + 2) × 6 = x Add the number of blocks run in the first and 2nd week. Then multiply the sum by the number of weeks (6).
Mathematics
1 answer:
Aneli [31]3 years ago
7 0
I would say the answer is B. 
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stion 1 OT 5A researcher recorded the number of swans and the number of ducks in a lake every month. Function s represents the n
Anon25 [30]

Given functions are

s(n)=2(1.1)^n+5_{}d(n)=4(1.08)^n+3

The total number of ducks and swans in the lake after n months can be determined by adding the functions s(n) and d(n).

t(n)=s(n)+d(n)

t(n)=(2(1.1)^n^{}+5)+(4(1.08)^n+3)

t(n)=2(1.1)^n+5+4(1.08)^n+3

t(n)=2(1.1)^n+4(1.08)^n+5+3

t(n)=2(1.1)^n+4(1.08)^n+8

Taking 2 as common, we get

t(n)=2\lbrack(1.1)^n+2(1.08)^n+4\rbrack

Hence The total number of ducks and swans in the lake after n months is

t(n)=2\lbrack(1.1)^n+2(1.08)^n+4\rbrack

8 0
1 year ago
How do you do this question?
daser333 [38]

Answer:

B. 1/2

Step-by-step explanation:

\lim_{z \to 0} \frac{g(z)e^{-z}-3}{z^{2}-2z}

If we plug in 0 for z, we get 0/0.  Apply l'Hopital's rule.

\lim_{z \to 0} \frac{-g(z)e^{-z}+g'(z)e^{-z}}{2z-2}

Now when we plug in 0 for z, we get:

\frac{-g(0)e^{0}+g'(0)e^{0}}{2(0)-2}\\\frac{-g(0)+g'(0)}{-2}\\\frac{-3+2}{-2}\\\frac{1}{2}

4 0
2 years ago
Q5 Q6.) Find the exact value of the six trigonometric functions of theta.
lilavasa [31]
5y - 2x + 1 = 0.
5y = 2x-1.

y = 2/5 x - 2/5

this tells us that tan(theta) = 2/5
sin(theta)/sqrt(1-sin^2(theta)) = 2/5
x/sqrt(1-x^2)=2/5
x^2/(1-x^2)=4/25
25x^2=4-4x^2
29x^2=4
x^2=4/29
x = -2/sqrt(29) because quadrant III
cos(x) = sqrt(1-4/29) = -5/sqrt(29)


tan(theta)=2/5
cos(theta)=-5/sqrt(29)
sin(theta)=-2/sqrt(29)
cot(theta)=5/2
sec(theta)=-sqrt(29)/5
csc(theta)=-sqrt(29)/2



5 0
3 years ago
Read 2 more answers
EVALUATE F(X)=1/3X FOR X=4
ollegr [7]
Simply plug in x = 4 in to the function

f(4) = 1/3 * 4

f(4) = 4/3
5 0
3 years ago
Write an equation in slope-intercept
Finger [1]
Y=2/3x-5

That is the regular slope-intercept form
4 0
3 years ago
Read 2 more answers
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