Answer:
x=4
Step-by-step explanation:
6^x = 1296
Take the log base 6 on each side
log6(6^x) = log6(1296)
Rewrite 1296 as 6^4
x = log 6(6^4)
We know that log( a^b) = b log (a)
x = 4 log6(6)
We know that loga(a) =1
x = 4 *a
x =4
Answer:
Therefore the concentration of salt in the incoming brine is 1.73 g/L.
Step-by-step explanation:
Here the amount of incoming and outgoing of water are equal. Then the amount of water in the tank remain same = 10 liters.
Let the concentration of salt be a gram/L
Let the amount salt in the tank at any time t be Q(t).

Incoming rate = (a g/L)×(1 L/min)
=a g/min
The concentration of salt in the tank at any time t is =
g/L
Outgoing rate =



Integrating both sides

[ where c arbitrary constant]
Initial condition when t= 20 , Q(t)= 15 gram


Therefore ,
.......(1)
In the starting time t=0 and Q(t)=0
Putting t=0 and Q(t)=0 in equation (1) we get









Therefore the concentration of salt in the incoming brine is 1.73 g/L
Answer:
what's the question that you need answered?
Step-by-step explanation:
?
Answer: The 2nd option is correct.
Step-by-step explanation:
Since you have started off with 4 players, the number line needs to start at 5, because 9 - 4 = 5. This gives us the answer of the second option, because it starts at 5 and goes to the positive side.