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4 years ago

The force created by moving, charged particles is called __________.

Physics

2 answers:

FrozenT [24]4 years ago

3 0

The correct answer is - A. <em>electromagnetic force</em>

mario62 [17]4 years ago

3 0

The answer for this question is electromagnetic force

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A net force of 25N causes an object to accelerate at 4m/s^2. what is the mass of the object?

Doss [256]

Answer:

6.25 kg

Explanation:

Fnet=ma

m=Fnet/a

m=25/4

m=6.25kg

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3 years ago

Explain the expression “light travels at a speed”.

Anestetic [448]

Some things travel faster than the speed of light

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3 years ago

You have 80 g of 60oC water and 80 g or 10oC water. What is the final temperature when the two are mixed? Explain.

blondinia [14]

The answer is 35 degrees Celsius

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3 years ago

Read 2 more answers

A passenger at an airport pulls a rolling suitcase by its handle. If the force used is 10 N and the handle makes an angle of 25

Deffense [45]

Answer:

W= 1812.6 J

Explanation:

Work (W) is defined as the scalar product of force F by the distance (d) the body travels due to this force.

W= F*d* cosα Formula ( 1)

Where:

F is the force in Newtons (N)

d is the displacemente in meters (m)

α : Angle formed between force and displacement

Data

F = 10 N

d = 200 m

α = 25°

Work done by the pulling force while the passenger walks 200 m

We replace data in the formula (1)

W= F*d* cosα

W= (10 N)*(200 m)* cos25°

W= 1812.6 (N*m)

W= 1812.6 J

6 0

3 years ago

You illuminate a slit with a width of 71.7 μm with a light of wavelength 737 nm and observe the resulting diffraction pattern on

miskamm [114]

To solve this problem we will apply the concepts related to the double slit-experiment. Under this concept we understand the relationship between the minimum angle, depending on the order of the fringes, the wavelength and the distance between slits. Therefore we have the following relation,

$sin(\theta_{min}) = \frac{m\lambda}{D}$

Here,

m = Order of the fringes

D = Distance between slits

$\lambda$ = Wavelength

Replacing with our values we have,

$sin(\theta_{min}) = \frac{(1)(737*10^{-9})}{71.7*10^{-6}m}$

$sin(\theta_{min}) = 0.01028$

Through the relationship between distances then we have that the basic amplification distance is given by the relationship between the distance of the slit L and the angle, then

$Y=Lsin\theta$

$Y =2.27*0.01028$

$Y =0.0233m$

Thus the width of the central maximum is

$W=2Y=2*0.0233$

$W = 0.0466m$

Therefore the widht is 0.466m

6 0

4 years ago