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galben [10]
3 years ago
7

If Mitzi has two dogs, a puppy that weighs 25 pounds and an adult that weighs 80 pounds, how much will it cost to bathe them bot

h? $105 $115 $150 $160
Mathematics
1 answer:
Sidana [21]3 years ago
4 0

Answer:

The correct answer is A) $105

Step-by-step explanation:

In this real-world problem,  the cost to groom both dogs is (the puppy) + (the adult dog) = x.

For the first step, y = 40, if x <= 25.

y = 50, if 25 < x < 50.

if x >= 50, then y = 0.50x + 25

So therefore, substitute the puppy + adult dog = x

25 + 80 = x

105 = x

So, the final answer is $105.

It's on Edgen.

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scZoUnD [109]

Hey there!

This grocer is mixing two kinds of coffee. I always love the smell of coffee!

We will say that x sells for $1.15 per pound and y sells for $2.75 per pound.

Altogether there are 24 pounds of coffee he is selling.

The algebraic equation would be x + y = 24

At $1.30 per pound, he will make 24 * $1.30 = $31.2

So, how many of the x and y kinds of coffee should he use to make the $1.30 per pound mixture which will net him $31.2?

The algebraic equation would be 1.15x + 2.75y = 31.2

We now have two equations :

x+y = 24

1.15x + 2.75y = 31.2

Substituting x= 24 -y in the second equation gives us

1.15(24-y) + 2.75y = 31.2

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27.6 + 1.6y = 31.2

1.6y = 31.2 - 27.6

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x = 24 -2.25

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So, he will use 21.75 pounds of the $1.15 per/lb one and another 2.25 pounds of the $2.75per/lb one.

~Done~

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Step-by-step explanation:

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