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2 years ago

What is the interquartile range of this set of data? 15,19,20,25,31,38,41

Mathematics

1 answer:

cupoosta [38]2 years ago

7 0

Answer: 19.

Step-by-step explanation:

1: Place your numbers in numerical order from smallest to largest; 15,19,20,25,31,38,41.

2. Find your median in the set of numbers; 15,19,20,25,31,38,41.

3. Find Q1 and Q3 in your set of numbers by placing parentheses around the median you have just found. (15,19,20),25,(31,38,41.)

4. In this instance, you need to find the medians of the two number sets in parentheses; (15,19,20), 19 being Q1, and (31,38,41), 38 being Q3.

5. Using the interquartile range formula; Q3-Q1= IQR, plug in your numbers.

38-19=19, making the answer 19.

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<h3>Given:-</h3>

The hypotenuse of a right angle triangle is 13cm.

One other side of the triangle is 1cm shorter than the hypotenuse.

Find the third scale of the triangle .

<h3>Solution:- </h3>

Let the third Side be x.

According to the question,

★ Hypotenuse = 13 cm

★ Other side = Hypotenuse - 1 [ Given ]

= 13 cm - 1 cm

= 12 cm

Now,

By pythagoras theorem,

13² = 12² + x²

⇒ 169 = 144 + x²

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Step-by-step explanation:

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Step-by-step explanation:

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3[(15 - 3) squared divided by 4]
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(Make sure to set f(x) to zero)

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Next, factor 5x^2 + 5x and -x - 1 separately. Make sure that they have the same quantity on the inside: $0=5x(x+1)-1(x+1)$

Now you can rewrite the equation as: $0=(5x-1)(x+1)$

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