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Tresset [83]
3 years ago
5

Comparing objects in a related group can reveal patterns among them. These patterns in turn can help us learn more about those o

bjects than we could by studying each individually.
With this goal in mind, watch this animation of the planets in the Solar System and select all of the following choices that describe the patterns that you've observed. As you do so, think about the implications of how the Solar System may have formed.
Choose one or more:
A. The orbits of the outer planets (those most distant from the Sun) are spaced farther apart from one another than the orbits of the inner planets.
B. Planets orbit the Sun in random directions.
C. All planets orbit the Sun in the same direction.
D. The size of all planets increases with distance from the Sun.
E. The orbits of the planets are evenly distributed in distance from the Sun.
F. All planets orbit the Sun in a roughly flat plane.
G. The closest planets to the Sun are much smaller than the planets that are farther away.
H. All planets orbit the Sun in a spherical distribution.
Physics
1 answer:
rosijanka [135]3 years ago
5 0

Answer:

C. All planets orbit the Sun in the same direction.

E. The orbits of the planets are evenly distributed in distance from the Sun.

F. All planets orbit the Sun in a roughly flat plane.

Explanation:

As we can see that due to big bang theory of planet formation we can say all planets revolve around the sun in circular orbit with almost in same plane

Size of the planets are unevenly distributed and they all revolve around the sun in same directions

so here correct options are

C. All planets orbit the Sun in the same direction.

E. The orbits of the planets are evenly distributed in distance from the Sun.

F. All planets orbit the Sun in a roughly flat plane.

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A fisherman casts his lure at an angle of 33 degrees above the horizontal. The lure reaches a maximum height of 2.3 m. Assuming
omeli [17]

Answer:

12.32 m/s

Explanation:

Using the formula of maximum height of a projectile,

H = u²sin²Ф/2g................... Equation 1

Where H = maximum height, u = initial velocity, Ф = angle of projection, g = acceleration due to gravity

make u the subject of the equation

u = √(2Hg/sin²Ф)............ Equation 2

Given: H = 2.3 m, Ф = 33°, g = 9.8 m/s²

Substitute into equation 2

u = √[(2×2.3×9.8)/sin²33°]

u =√ [45.08/(0.545)²]

u = 45.08/0.297

u = √(151.785)

u = 12.32 m/s

3 0
3 years ago
When a man travel from hilly to terai what will happen to weight and why?
juin [17]

Answer:

When a man travels from Hilly region to Terai region, his weight gradually increases because the value of g is more at the Terai region than that in hilly region. 3. An object weights 20 N in air and 16 N in liquid, then answer the following questions.

Explanation:

because the value of g is more at the Terai region than that in hilly region. 3. An object weights 20 N in air and 16 N in liquid, then answer the following questions.

6 0
3 years ago
Sound with frequency 1300 Hz leaves a room through a doorway with a width of 1.03 m . At what minimum angle relative to the cent
AlexFokin [52]

Answer:

  about 14.7°

Explanation:

The formula for the angle of the first minimum is ...

  sin(θ) = λ/a

where θ is the angle relative to the door centerline, λ is the wavelength of the sound, and "a" is the width of the door.

The wavelength of the sound is the speed of sound divided by the frequency:

  λ = (340 m/s)/(1300 Hz) ≈ 0.261538 m

Then the angle of interest is ...

  θ = arcsin(0.261538/1.03) ≈ 14.7°

At an angle of about 14.7°, someone outside the room will hear no sound.

6 0
3 years ago
For copper, ρ = 8.93 g/cm3 and M = 63.5 g/mol. Assuming one free electron per copper atom, what is the drift velocity of electro
viktelen [127]

Answer:

V_d = 1.75 × 10⁻⁴ m/s

Explanation:

Given:

Density of copper, ρ = 8.93 g/cm³

mass, M = 63.5 g/mol

Radius of wire = 0.625 mm

Current, I = 3A

Area of the wire, A = \frac{\pi d^2}{4} = A = \frac{\pi 0.625^2}{4}

Now,

The current density, J is given as

J=\frac{I}{A}=\frac{3}{ \frac{\pi 0.625^2}{4}}= 2444619.925 A/mm²

now, the electron density, n = \frac{\rho}{M}N_A

where,

N_A=Avogadro's Number

n = \frac{8.93}{63.5}(6.2\times 10^{23})=8.719\times 10^{28}\ electrons/m^3

Now,

the drift velocity, V_d

V_d=\frac{J}{ne}

where,

e = charge on electron = 1.6 × 10⁻¹⁹ C

thus,

V_d=\frac{2444619.925}{8.719\times 10^{28}\times (1.6\times 10^{-19})e} = 1.75 × 10⁻⁴ m/s

4 0
3 years ago
Read 2 more answers
Which formula correctly shows how to calculat the time taken, given the average velocity and the displacement
Alisiya [41]
We're so good here on Brainly, we can answer it
even WITHOUT seeing the choices.

     Time = (displacement) / (magnitude of average velocity) .
8 0
3 years ago
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