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AveGali [126]
3 years ago
13

Any temperature on the Kelvin scale can be changed to Celsius degrees by?

Physics
1 answer:
igor_vitrenko [27]3 years ago
5 0
           0° C  =  273.15 K

Notice that the K temp is 273.15 more than the C temp.

So, to get any Celsius temp, subtract 273.15 from the Kelvin temp.
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If the mass of an object on earth is 40 kilograms it’s mass on the moon is
g100num [7]
Speaking bout mass,
it's mass is still 40Kg on the moon

but it's Weight on the moon is 1/6mg
5 0
4 years ago
Automobile A and B are initially 30 m apart travelling in adjacent highway lanes at speeds VA = 14.4 km/hr., VB 23.4 km/hr. at t
marshall27 [118]

Answer:

        x = 240 m

Explanation:

This is a kinematics exercise

Let's fix our frame of reference on car A

           x = x₀ₐ+ v₀ₐ t + ½ aₐ t²

         

the initial position of car a is zero

           x = 0 + v₀ₐ t + ½ 0.8 t²

for car B

          x = x_{ob} + v_{ob} t - ½ a_b t²

     

car B's starting position is 30 m

         x = 30 + v_{ob} t - ½ 0.4 t²

at the point where they meet, the position of the two vehicles is the same

         0 + v₀ₐ t + ½ 0.8 t² = 30 + v_{ob} t - ½ 0.4 t²

let's reduce the speeds to the SI system

        v₀ₐ = 14.4 km / h (1000 m / 1 km) (1h / 3600s) = 4 m / s

        v_{ob} = 23.4 km / h = 6.5 m / s

        4 t + 0.4 t² = 30 + 6.5 t - 0.2 t²

        0.2 t² - 2.5 t - 30 = 0

        t² - 12.5 t - 150 = 0

we solve the quadratic equation

       t = \frac{12.5 \pm \sqrt{12.5^2 + 4 \ 150}  }{2}

       t = \frac{12.5 \  \pm 27.5}{2}

       t₁ = 20 s

       t₂ = -7.5 s

time must be a positive quantity so the correct result is t = 20 s

let's look for the distance

        x = 4 t + ½ 0.8 t²

        x = 4 20 + ½ 0.8 20²

        x = 240 m

8 0
3 years ago
A rock has a specific gravity of 2.32 and a volume of 8.64 in3 how much does it weigh
lianna [129]

Answer: 3.21 N

Specific\hspace{1mm} gravity = \frac {Density\hspace{1mm}of\hspace{1mm}substance}{Density\hspace{1mm} of \hspace{1mm}water}

\Rightarrow Density \hspace{1mm}of\hspace{1mm}substance= 2.32\times 1000\hspace{1mm} kg/m^3 = 2320\hspace{1mm}kg/m^3\\ Mass =Density\times volume\\ \Rightarrow 2320 \hspace{1mm} kg/m^3\times 8.64 \hspace{1mm}in^3\times \frac {1.64\times10^{-5} m^3}{1\hspace{1mm}in^3}=0.328 kg

For weight, we will multiply by g=9.8 m/s^{-2}

weight= 0.328\times9.8=3.21\hspace{1mm}N

Hence, the rock would weigh 3.21 N.

3 0
3 years ago
A rock is thrown from a height of 2.0 m at a window that is located 9.0 m above the ground. The initial velocity of the rock is
ELEN [110]

Answer:

The value is  x = 11.81 \ m

Explanation:

From the question we are told that

   The height is h =  2.0 m

   The height of the window is d = 9.0 \ m

    The initial velocity of the rock is u =  20 \ m/s

    The angle at which it is thrown is \theta  =  40

Generally the  vertical component of the velocity of the stone is mathematically represented as

    v_y = 20 sin (40)

=>v_y = 12.86 \ m/s

Generally the height of the window from the ground is mathematically represented as using kinematic equation as

      d = h  +  v_yt + \frac{1}{2} gt^2

=>   9 = 2  +12.86 t + \frac{1}{2} * - 9.8 t^2

Here g is negative -9.8 m/s^2 because the direction of the stone is against gravity

   So

       4.9 t^2 -12.86 t + 7 =0

Solving this quadratic equation using quadratic formula we obtain

     t = 0.770 s

Generally the velocity of the stone on the x axis is mathematically represented as

       v_x =  20 * cos(40 )

=>    v_x =  15.32 \  m/s

Generally the distance between the person throwing the rock and the window is mathematically represented as

       x =  v_x * t

=>    x =  15.32 * 0.771

=>    x = 11.81 \ m

8 0
3 years ago
If 5kg Stone and 1kg stone throw the from the building which will land more fa ster and why?​
sweet [91]

Answer:

Both stones will land at the same time because both stones will fall with the same acceleration through the same height.

Explanation:

We are given that

Mass of stone ,m1=5 Kg

Mass of stone, m2=1 kg

We have to find which stone more faster will land and why.

h=u+\frac{1}{2}gt^2

Initial velocity of both stones=0

h=\frac{1}{2}gt^2

t^2=\frac{h}{g}

t=\sqrt{\frac{h}{g}}

t_1=t_2=\sqrt{\frac{h}{g}}

Because both stones are thrown from the same height.

Both stones will land at the same time because both stones will fall with the same acceleration through the same height  and the acceleration  does not depend of its mass.

5 0
3 years ago
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