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Maksim231197 [3]

3 years ago

11

Which happens to the magnetic field of a wire when you change the direction of the current in the wire? It becomes stronger. It

becomes weaker. It changes direction too. It stays the same.

1 answer:

scZoUnD [109]3 years ago

7 0

Answer C. The magnetic field changes direction too.

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Why the specific heat capacity of the sun remain constant<br><br>

gayaneshka [121]

The heat remains constant because there’s nothing to cool it down

7 0

3 years ago

A 200g of iron at 120 degrees and a 150 g piece of copper at -50 degrees are dropped into an insulated beaker containing 300 g o

kodGreya [7K]

Answer:

T = 15.03°C

Explanation:

given data:

copper specific heat = Sc = 0.385 J/g °C

iron specific iron = Si = 0.450 J/g °C

specific heat of ethanol = Se = 2.46 J/g °C

net heat loss is equal to zero

$(m*S*\Delta T)_{copper} +(m*S*\Delta T)_ {iron} +(m*S*\Delta T)_ {ethanol} = 0$

$150*0.385 *( T - (-50)) + 200*0.450*(T - 120) + 300*2.46 * (T -20) = 0$

$57.75( T - (-50)) + 0.90(T - 120) +738(T -20) = 0$

$57.75T + 2887.5 + 0.90T - 108 + 738T - 14760 = 0$

$57.75T + 0.90T+738T = - 2887.5 + 108+14760$

$796.65T= 11980.5$

T = 15.03°C

4 0

3 years ago

A beam of yellow light is made to pass through two slits that are 3.0 x 10−3 meters apart. On a screen 2.0 meters away from the

lakkis [162]

Answer:

585 nm

Explanation:

The formula that gives the position of the m-th maximum (bright fringe) relative to the central maximum in the interference pattern produced by diffraction from double slit is:

$y=\frac{m\lambda D}{d}$ $\Delta y =\frac{m\lambda D}{d}$

where

m is the order of the maximum

$\lambda$ is the wavelength

D is the distance of the screen from the slits

d is the separation between the slits

The distance between two consecutive bright fringes therefore is given by:

$\Delta y = \frac{(m+1)\lambda D}{d}-\frac{m\lambda D}{d}=\frac{\lambda D}{d}$

In this problem we have:

$\Delta y = 3.9\cdot 10^{-4} m$ (distance between two bright fringes)

D = 2.0 m (distance of the screen)

d = 3.0 x 10−3 m (separation between the slits)

Solving for $\lambda$ , we find the wavelength:

$\lambda=\frac{\Delta y d}{D}=\frac{(3.9\cdot 10^{-4})(3.0\cdot 10^{-3})}{2.0}=5.85\cdot 10^{-7} m = 585 nm$

4 0

3 years ago

A 50.0 g toy car is released from rest on a frictionless track with a vertical loop of radius R (loop-the-loop). The initial hei

Mariana [72]

Answer:

the speed of the car at the top of the vertical loop $v_{top} = 2.0 \sqrt{gR \ \ }$

the magnitude of the normal force acting on the car at the top of the vertical loop $F_{N} = 1.47 \ \ N$

Explanation:

Using the law of conservation of energy ;

$mgh = mg (2R) + \frac{1}{2}mv^2_{top}\\\\mg ( 4.00 \ R) = mg (2R) + \frac{1}{2}mv^2_{top}\\\\g(4.00 \ R) = g (2R) + \frac{1}{2}v^2 _{top}\\\\v_{top} = \sqrt{2g(4.00R - 2R)}\\\\v_{top} = \sqrt{2g(4.00-2)R$

$v_{top} = 2.0 \sqrt{gR \ \ }$

The magnitude of the normal force acting on the car at the top of the vertical loop can be calculated as:

$F_{N} = \frac{mv^2_{top}}{R} \ - mg\\\\F_{N} = \frac{m(2.0 \sqrt{gR})^2}{R} \ - mg\\\\F_{N} = [(2.0^2-1]mg\\\\F_{N} = [(2.0)^2 -1) (50*10^{-3} \ kg)(9.8 \ m/s^2]\\\\$

$F_{N} = 1.47 \ \ N$

4 0

4 years ago

Magnetic fields are produced either by electric currents or time-varying electric fields.

Fynjy0 [20]

Answer:

option (a)

Explanation:

The magnetic field is produced by the electric current, and the direction of magnetic field is given by the Maxwells' right hand rule.

The magnetic field is also be produced by the time varying magnetic fields.

6 0

3 years ago