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Viktor [21]
3 years ago
9

Need help math test pleassssws

Mathematics
1 answer:
Kryger [21]3 years ago
5 0

Answer:

Yes, the number of cells is a linear function (linear and a function).

Step-by-step explanation:

Ok, I may be wrong, but please don't hate me!!!

The number of cells is a function because the number of cells increased by the same amount (times 4 cells) each day.

The number of cells is linear because it increased by the same amount each day and if you placed this function on a graph, you could interpret the values of the number of cells without needing to know the function.

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a band of 45 ewoks crash-landed in the forest last night. this sounds like a small problem, but the population will grow at the
kogti [31]

Given Information:

Starting population = P₀ = 45

rate of growth = 22%

Required Information:

Population every five years from this year to the year 2050 = ?

Answer:

Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\

Step-by-step explanation:

The population growth can be modeled as an exponential function,

P(t) = P_0e^{rt}

Where P₀ is the starting population, r is the rate of growth of the population and t is the time in years.

We are given that starting population of 45 and growth rate of 22%

P(t) = 45e^{0.22t}

Assuming that the starting year is 2020,

Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\

Therefore, the starting population of ewoks was 45 in 2020 and increased to 33,079 by 2050 in a time span of 30 years.

8 0
3 years ago
Quadratic equations Please Help Me!!!!!!
igor_vitrenko [27]

The roots are 1 +√7 and 1 -√7.

<h3>What is Quadratic equation?</h3>

A quadratic equation in the variable x is an equation of the form ax² + bx + c= 0, where a, b, c are real numbers, a≠0

Given equation:

y= x²+2x-6

First,

Half the coefficient of x and add and subtract the square of (b/2)

y= x²+2x-6+(1)²-(1)²

y= x²+2x+(1)² -6 -(1)²

y= (x+1)² -7

Now, equate y=0

(x+1)² -7 =0

(x+1)² = 7

x+1= ±√7

x=1 ±√7

Hence, the roots are 1 +√7 and 1 -√7.

Learn more about quadratic equation here:

brainly.com/question/1962219

#SPJ1

7 0
2 years ago
Erica plotted the three towns closest to her house on a graph with town AA at (9, 12), town BB at (9, 7) and town CC at (1, 1).
Sliva [168]
To compute the distance between the points, we can apply the distance formula as shown below.

d = \sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2} }

In which x₁ and x₂ are the x-coordinates and y₁ and y₂ are the y-coordinates of the two points. Thus, applying this with the segments AABB, AACC, and BBCC, we have

\overline{AABB} = \sqrt{(9-9)^{2} + (12-7)^{2}} = 5
\overline{AACC} = \sqrt{(9-1)^{2} + (12-1)^{2}} = \sqrt{185}
\overline{BBCC} = \sqrt{(9-1)^{2} + (7-1)^{2}} = 10

Now that we have the lengths of all the sides of ΔAABBCC, we can find the missing angles using the Law of Cosines.

Generally, we have

c^{2} = a^{2} + b^{2} - 2abcosC

or

C = cos^{-1} (\frac{a^{2} + b^{2} - c^{2}}{2ab})

Hence, we have

\angle AA = cos^{-1} (\frac{(\sqrt{185})^{2} + 5^{2} - 10^{2}}{2(5)(\sqrt185)})
\angle BB= cos^{-1} (\frac{5^{2} + 10^{2} - (\sqrt{185})^{2}}{2(5)(10)})
\angle CC= cos^{-1} (\frac{10^{2} + (\sqrt{185})^{2} - 5^{2}}{2(5)(\sqrt{185})})

Simplifying this, we have

\angle AA = 36.03^{0}
\angle BB = 126.87^{0}
\angle CC = 17.10^{0} 

Thus, from this, we can arrange the angles from smallest to largest: ∠CC, ∠AA, and ∠BB.

Answer: ∠CC, ∠AA, and ∠BB
3 0
3 years ago
5/8 ∙ 2/15 please answer
Phoenix [80]

Answer:

0.08333333333 or  1/2

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Find the percentage of data points that lie between -3.01 and 2.61?<br> z= (x-u) /o
Marat540 [252]

Answer:

To find the percetage of data points that lie between the points -3.01 and 2.61, on a normal distribution we're going to need the help of a calculator. The result is: 99.42%

Attached you will find the graph that represents the result.

6 0
3 years ago
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